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If \(A = \{ 1,2,3,4 \}, B = \{ 4,5,6,7 \},\) determine the following sets: (i) \(A \cap B\) (ii) \(A \cup B\) (iii) \(A \backslash B \) (i) By definition, \(\cap\) tells us that we want to find the common elements between the two sets. In this case, it is 4 only. Thus \(A \cap B = \{ 4 \} \). (ii) By definition, \(\cup\) tells us that we want to combine all the elements between the two sets. In this case, it is \(A\cup B = \{1,2,3,4,5,6,7 \} \). (iii) By definition, \( \backslash \) tells us that we want to look for elements in the former set in that doesn't appear in the latter set. So \(A \backslash B = \{1,2,3\} \). \(_\square\)
Consider the same example above. If the element \(4\) is removed from the set \(B\), solve for (i), (ii), (iii) as well. (i) Since there is no common elements in sets \(A\) and \(B\), then \(A \cap B = \phi \) or \(A \cap B = \{ \} \). (ii) Because the element \(4\) is no longer repeated, then \(A \cup B \) remains the same. (iii) Since \(A\) and \(B\) no longer share any common element, \(A\backslash B \) is simply equals to set \(A\), which is \(\{1,2,3,4 \} \). \(_\square\)

If \(P=\{2, 5, 6, 3, 7\}\) and \(Q=\{1, 2, 3, 8, 9, 10\},\) which of the following Venn diagrams represents the relationship between the two sets?

\[\large\color{darkred}{B=\{ \{ M,A,T,H,S \} \}}\]

Find the cardinal number of the set \(\color{darkred}{B}\).

Note: The cardinal number of a set is equal to the number of elements contained in the set.

Bonus question given with the picture.

Join the brilliant classes and enjoy the excellence. also checkout foundation assignment #2 for jee..

Consider the set \( \lbrace{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\rbrace}\).

For each of its subsets, let \( M \) be the greatest number. Find the last three digits of the sum of all the \( M \)'s.

Assume that \(0\) is the greatest number of the empty subset.

The number of subsets in set A is 192 more than the number of subsets in set B. How many elements are there in set A?

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Set Operations

Set operations is a concept similar to fundamental operations on numbers. Sets in math deal with a finite collection of objects, be it numbers, alphabets, or any real-world objects. Sometimes a necessity arises wherein we need to establish the relationship between two or more sets. There comes the concept of set operations.

There are four main set operations which include set union, set intersection, set complement, and set difference. In this article, we will learn the various set operations, notations of representing sets, how to operate on sets, and their usage in real life.

1.
2.
3.
4.

What are Set Operations?

A set is defined as a collection of objects. Each object inside a set is called an 'Element'. A set can be represented in three forms. They are statement form, roster form , and set builder notation . Set operations are the operations that are applied on two or more sets to develop a relationship between them. There are four main kinds of set operations which are as follows.

  • Union of sets
  • Intersection of sets
  • Complement of a set
  • Difference between sets/Relative Complement

Before we move on to discuss the various set operations, let us recall the concept of Venn diagrams as it is important in understanding the operations on sets. A Venn diagram is a logical diagram that shows the possible relationship between different finite sets. The Venn diagram can be represented as follows.

Set Operations Venn Diagram

Basic Set Operations

Now that we know the concept of a sets and Venn diagram, let us discuss each set operation one by one in detail. The various set operations are:

Union of Sets

For two given sets A and B, A∪B (read as A union B) is the set of distinct elements that belong to set A and set B or both. The number of elements in A ∪ B is given by n(A∪B) = n(A) + n(B) − n(A∩B), where n(X) is the number of elements in set X. To understand this set operation of the union of sets better, let us consider an example: If A = {1, 2, 3, 4} and B = {4, 5, 6, 7}, then the union of A and B is given by A ∪ B = {1, 2, 3, 4, 5, 6, 7}.

Intersection of Sets

For two given sets A and B, A∩B (read as A intersection B) is the set of common elements that belong to set A and B. The number of elements in A∩B is given by n(A∩B) = n(A)+n(B)−n(A∪B), where n(X) is the number of elements in set X. To understand this set operation of the intersection of sets better, let us consider an example: If A = {1, 2, 3, 4} and B = {3, 4, 5, 7}, then the intersection of A and B is given by A ∩ B = {3, 4}.

Set Difference

The set operation difference between sets implies subtracting the elements from a set which is similar to the concept of the difference between numbers. The difference between sets A and set B denoted as A − B lists all the elements that are in set A but not in set B. To understand this set operation of set difference better, let us consider an example: If A = {1, 2, 3, 4} and B = {3, 4, 5, 7}, then the difference between sets A and B is given by A - B = {1, 2}.

Complement of Sets

The complement of a set A denoted as A′ or A c (read as A complement) is defined as the set of all the elements in the given universal set(U) that are not present in set A. To understand this set operation of complement of sets better, let us consider an example: If U = {1, 2, 3, 4, 5, 6, 7, 8, 9} and A = {1, 2, 3, 4}, then the complement of set A is given by A' = {5, 6, 7, 8, 9}.

Set Operations

The above image shows various set operations with the help of Venn diagrams. When the elements of one set B completely lie in the other set A, then B is said to be a proper subset of A. When two sets have no elements in common, then they are said to be disjoint sets . Now, let us explore the properties of the set operations.

Properties of Set Operations

The properties of set operations are similar to the properties of fundamental operations on numbers. The important properties on set operations are stated below:

  • Commutative Law - For any two given sets A and B, the commutative property is defined as, A ∪ B = B ∪ A This means that the set operation of union of two sets is commutative. A ∩ B = B ∩ A This means that the set operation of intersection of two sets is commutative.
  • Associative Law - For any three given sets A, B and C the associative property is defined as, (A ∪ B) ∪ C = A ∪ (B ∪ C) This means the set operation of union of sets is associative. (A ∩ B) ∩ C = A ∩ (B ∩ C) This means the set operation of intersection of sets is associative.
  • De-Morgan's Law - The De Morgan's law states that for any two sets A and B, we have (A ∪ B)' = A' ∩ B' and (A ∩ B)' = A' ∪ B'

Important Notes on Set Operations

  • Set operation formula for union of sets is n(A∪B) = n(A) + n(B) − n(A∩B) and set operation formula for intersection of sets is n(A∩B) = n(A)+n(B)−n(A∪B).
  • The union of any set with the universal set gives the universal set and the intersection of any set A with the universal set gives the set A.
  • Union, intersection, difference, and complement are the various operations on sets.
  • The complement of a universal set is an empty set U′ = ϕ. The complement of an empty set is a universal set ϕ′ = U.

Related Topics on Set Operations

  • Finite and Infinite Sets

Examples of Set Operations

Example 1: In a school, every student plays either football or soccer or both. It was found that 200 students played football, 150 students played soccer and 100 students played both. Find how many students were there in the school using the set operation formula.

Solution: Let us represent the number of students who played football as n(F) and the number of students who played soccer as n(S). We have n(F) = 200, n(S) = 150 and n(F ∩ S) = 100. We know that,

n(F∪S) = n(F) + n(S) − n(F∩S)

Therefore, n(F∪S)=(200+150)−100

n(F∪S) = 350 − 100 = 250

Answer: Hence the total number of students in the school is 250.

Example 2: If A = {a, b, c, d, e}, B = {a, e, i, o, u}, U = {a, b, c, d, e, f, g, h, i, j, k, l, o, u}. Perform the following operations on sets and find the solutions.

a) A ∪ B b) A ∩ B c) A′ d) A - B

Solution: a) A ∪ B = {a, b, c, d, e, i, o, u}

b) A ∩ B = {a, e}

c) A' = {f, g, h, i, j, k, l, o, u}

d) A - B = {b, c, d}

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problem solving involving 2 sets

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Practice Questions on Set Operations

Faqs on set operations, what are set operations in set theory.

Set operations are the operations that are applied on two or more sets to develop a relationship between them. There are four main kinds of set operations.

What are the Different Set Operations?

There are four main kinds of set operations which are:

How Do We Use Set Operations in Real Life?

A set is a collection of elements. Some real-life examples of sets are a list of all the states in a country, a list of all shapes in geometry , list of all whole numbers from 1 to 100. We can determine the common regions using the intersection set operation.

How do you Solve Set Operations Problems?

To solve set operation problems we use a Venn diagram to represent the relationship between the sets and apply the set operations formula for union, intersection, difference, or complement of a set.

Which of the Set Operations are Commutative and not Commutative?

Union and Intersection of sets are set operations that are commutative whereas the set difference is not commutative.

What are the Set Operations Symbols?

There are different symbols used for different set operations are referred as set notations . For the union of sets, we use ' ∪ ', for the intersection of sets, we use '∩', for the difference of sets, we use ' - ', and for the complement of a set A, we write it as A' or A c .

How do you Find the Difference Between the Two Sets?

For any two sets A and B, the difference A - B lists all the elements in set A that are not in set B.

How do you Find the Complement of a Set?

Given the universal set 'U' and set A, the complement of a set A is defined as the set of all elements in the universal set that are not present in set A.

What are the Union and Intersection operations of Sets?

For any two sets A and B, the union is defined as the combination of elements in both set A and B. Intersection of sets gives the common elements in set A and set B.

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Solving equations involving two sets

Out of curiosity, how would one go about solving an equation involving two sets? For example,

$$ \{1, 2, 3\} = \{a + b + c, a + b - c, a - b + c, a - b - c\} $$

An intuitive solution to this is $ \{a = 2, b = 0.5, c = 0.5\} $ , but is there a specific process?

  • elementary-set-theory
  • 1 $\begingroup$ Set's dont have a strict order. So you have to go through all possibilities, for example $1=a+b+c$, $1=a+b-c$ and $1=a-b-c$. I don't if two sets with different cardinality can be set equal. Don't think so. $\endgroup$ –  vitamin d Commented Feb 20, 2021 at 19:15
  • 1 $\begingroup$ $\{1,2,3\}$ has three elements and $\{a+b+c,a+b−c,a−b+c,a−b−c\}$ has $4$ so the second must have repeated elements. $\endgroup$ –  fleablood Commented Feb 20, 2021 at 19:55

2 Answers 2

Notice the set on the left has three distinct elements, but the set on the right has four representations so two of those represetations are of the same number.

So we have six options.

$a+b+c = a+b-c$ and $c = 0$ and we have the values $a+b$ and $a-b$ . But that's only two different values (or fewer) and we have exactly $3$ so that's impossible.

$a+b + c = a-b+c$ and $b =0$ and have the values $a+c$ and $a-c$ and that's the same problem.

$a+b+c = a-b-c$ and $b+c= 0$ and $b=-c$ and we have the values $a, a+2b, a-2b$ . We'll get back to this.

$a+b-c = a-b + c$ and $b-c=0$ and $b=c$ and we have the values $a+2b; a; a-2b$ . That will have the same solutions as above.

$a+b-c=a-b-c$ and $b=0$ and we have the same problem we had earlier.

Or $a-b+c = a-b-c$ adn $c=0$ and we have the same problem from the very begining.

So either way we have $a,a+2b, a-2b = 1,2,3$ .

$a\pm 2b, a , a\pm 2b$ are in arithmetic progression so we must have either $a-2b < a < a+2b$ and $a-2b = 1, a=2, a+2b=3$ or $a+2b < a < a-2b$ and $a+2b = 1, a=2, a-2b =3$

So we must have $a=2$ and $b =\pm 0.5$ and $c = \pm 0.5$ (so there are four sets of solutions.)

There isn't really any way to do this in general.

fleablood's user avatar

In the right set, two elements are equal. The only possibilities are $$a+b+c=a-b-c$$ or $$a+b-c=a-b+c$$ which gives $$b=\pm c$$

The equation becomes $$\{a-2b,a,a+2b\}=\{1,2,3\}$$

The sum gives $ 3a=6 $ and $ a=2$ .

hamam_Abdallah's user avatar

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problem solving involving 2 sets

  • Math Article

Sets Questions

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Sets questions with solutions are given here for students to make them understand the concept easily. Practising these problems will help to go through the concept of sets theory . It is an important chapter for Class 11 students, hence we have given the questions based on the NCERT curriculum, with respect to the CBSE syllabus.

A brief introduction for each sub-topic of sets is also provided so that students can solve the questions quickly. Some of the basic definitions related to this concept are given below. Also, read Sets For Class 11 , here.

Sets : A collection of well-defined objects. It is denoted by capital letters.

Example: A = {1, 2, 3, 4, 5..}.

Here, set A is a collection of all natural numbers.

Roster form of sets: All elements are written in curly braces { }, separated by commas.

Example: R = {1, 3, 7, 21, 2, 6, 14, 42}.

Set Builder Form: The elements of the set represent a common property.

Example, R = {x : x is a vowel in English alphabet}

First, let us see some questions based on the representation of sets.

Questions on Sets with Solutions

1. Write the solution set of the equation x 2 – 4=0 in roster form.

Solution: x 2 – 4 = x 2 – 2 2 = (x – 2) (x + 2)

Thus, A = {-2, 2}

2. Write the set A = {1, 4, 9, 16, 25, . . . } in set-builder form.

Solution: If we see the pattern here, the numbers are squares of natural numbers, such as:

A = {x : x is the square of a natural number}

Or we can write;

A = {x : x = n 2 , where n ∈ N}

A set with no elements. Also called a void set or null set

A set with a definite number of elements (even with zero elements) is a finite set otherwise the set is infinite

Two sets that have the same elements are called equal sets.

3. Write an example of a finite and infinite set in set builder form.

Finite set, A = {x : x ∈ N and (x – 1) (x – 2) = 0}

Infinite Set, B = {x : x ∈ N and x is prime}

4. Write an example of equal sets.

Solution: Let there be two sets A and B

A is the set of letters in “ALLOY”

B is the set of letters in “LOYAL”

A = {A,L, O,Y}

B = {L,O,Y,A}

Therefore, in both sets, the elements are the same.

A set A is said to be a subset of set B if every element of A is also an element of B

Symbolically, A ⊂ B if a ∈ A ⇒ a ∈ B.

Collection of all subsets of a set.

5. Write the subsets of {1,2,3}.

Solution: Let A = {1, 2, 3}

The subsets of A are: φ, {1}, {2}, {3}, {1, 2}, {2, 3}, {1, 3}, {1, 2, 3}

6. Write {x: x ∈ R, 3 ≤ x ≤ 4} as an interval.

7. Write the interval (6, 12) in set builder form.

Let A be the interval (6, 12).

The interval (6, 12) in set builder form is

A = {x: x ∈ R, 6 < x < 12}

8. If set A = {1, 3, 5}, B = {2, 4, 6} and C = {0, 2, 4, 6, 8}. Then write the universal set for all three sets.

Solution: If U is the universal set for sets A, B and C, then: U = Elements of set A + Elements of set B + Elements of set C

U = {0, 1, 2, 3, 4, 5, 6, 8}

Also, read: Sets Subset And Superset

If A and B are two sets, then A union B will have all the elements of set A and set B. It is represented as A ∪ B.

: If A and B are two sets, then A intersection B will have common elements of set A and set B. It is represented as A ∩ B.

9. If A = { 2, 4, 6, 8} and B = { 6, 8, 10, 12}. Find A ∪ B.

Solution: A ∪ B = { 2, 4, 6, 8, 10, 12}

10. If A = { 2, 4, 6, 8} and B = { 6, 8, 10, 12}. Find A ∩ B.

Solution: A ∩ B = { 6, 8 }

Also, see : Operation On Sets Intersection Of Sets And Difference Of Two Sets

A ∪ B = B ∪ A (Commutative law) A ∩ B = B ∩ A (Commutative law)
(A ∪ B ) ∪ C = A ∪ ( B ∪ C) (Associative law ) ( A ∩ B ) ∩ C = A ∩ ( B ∩ C ) (Associative law)
A ∪ φ = A (Law of identity element, φ is the identity of ∪) φ ∩ A = φ, U ∩ A = A (Law of φ and U)
A ∪ A = A (Idempotent law) A ∩ A = A (Idempotent law)
U ∪ A = U (Law of U) A ∩ ( B ∪ C ) = ( A ∩ B ) ∪ ( A ∩ C ) (Distributive law )

11. If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8}. Find A ∪ B ∪ C.

Solution: A ∪ B ∪ C = {1, 2, 3, 4, 5, 6, 7, 8}

12. If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15}. Find A ∩ (B ∪ C).

As we know, A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

= {7, 9, 11} ∪ {11}

= {7, 9, 11}

If A and B are two sets, then the difference of set A and set B is a set that has elements of only set A, not B. It is represented as A – B.

13. If A = { 1, 2, 3, 4, 5, 6}, B = { 2, 4, 6, 8 }. Find A – B and B – A.

Solution: A – B = { 1, 3, 5 }

B – A = { 8 }

Clearly, A – B ≠ B – A

If A is a subset of universal set U, then the complement of a set A is the set that does not have any elements of A. It is denoted as A′.

A′ = {x : x ∈ U and x ∉ A }

A′ = U – A

14. If U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} and A = {1, 3, 5, 7, 9}. Find A′.

Solution: A′ = { 2, 4, 6, 8, 10 }

Video Lesson on What are Sets

problem solving involving 2 sets

Practice Questions

Solve the following questions on sets:

  • Check whether the given sets are equal sets: A = {1, 2, 3, 4} and B = {2, 4, 1, 3}.
  • Write the subsets for the set A = {1, 3, 5, 7}
  • Write the set A = {1, 2, 3, 4, 5, …} in set-builder form.
  • If A = {1, 3, 5, 7, 9, 11} and B = {1, 2, 3, 13}, the find A – B and B – A.
  • Find A ∪ (B ∪ C), if A = {1, 3, 5}, B = {2, 4, 6} and C = {1, 5, 7}.

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problem solving involving 2 sets

A servey was conducted among 300 students . It was found that 125 students like to play cricket . 145 students like to play football . 90 students like to play tennis . 32 students like to play exactly two games out of the three games. How many students like to play exactly one games .?

n(C) = 125, n(F) = 145, n(T) = 90 n(C ⋃ F ⋃ T) = 125 + 145 + 90 – [n(C ⋂ F) + n(F ⋂ T) + n(T ⋂ C)] + n(c ⋂ F ⋂ T) 300 = 360 – [n(C ⋂ F) + n(F ⋂ T) + n(T ⋂ C)] + n(c ⋂ F ⋂ T) n(C ⋂ F) + n(F ⋂ T) + n(T ⋂ C) = 60 + n(c ⋂ F ⋂ T)….(i) Also, given that, n(C ⋂ F) + n(F ⋂ T) + n(T ⋂ C) – 3[n(c ⋂ F ⋂ T)] = 32 n(C ⋂ F) + n(F ⋂ T) + n(T ⋂ C) = 32 + 3[n(c ⋂ F ⋂ T)]….(ii) From (i) and (ii), 60 + n(c ⋂ F ⋂ T) = 32 + 3[n(c ⋂ F ⋂ T)] 60 – 32 = 3[n(c ⋂ F ⋂ T)] – n(c ⋂ F ⋂ T) 2[n(c ⋂ F ⋂ T)] = 28 n(c ⋂ F ⋂ T) = 14 Number of students like to play exactly one game = n(C) + n(F) + n(T) – 2[n(C ⋂ F) + n(F ⋂ T) + n(T ⋂ C)] + 3[n(c ⋂ F ⋂ T)] = 125 + 145 + 90 – 2[32 + 3 × 14] + 3 × 14 = 360 – 148 + 42 = 254

problem solving involving 2 sets

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Video transcript

IMAGES

  1. Ex 1: Set Problem Solving

    problem solving involving 2 sets

  2. problem solving involving sets using venn diagrams ppt

    problem solving involving 2 sets

  3. Solving Word Problems With Venn Diagrams Two Sets

    problem solving involving 2 sets

  4. Ex: Set Problem Solving

    problem solving involving 2 sets

  5. Word Problem Involving Sets

    problem solving involving 2 sets

  6. Ex 1: Set Problem Solving

    problem solving involving 2 sets

VIDEO

  1. Problem Solving Involving on Sets

  2. I Problem Solving involving Simultaneous Linear Equations Q 28 b

  3. 4 Tricky Riddles with Matchsticks. Solve It!

  4. PROBLEM SOLVING INVOLVING CONIC SECTIONS

  5. Math 5 PROBLEM SOLVING INVOLVING MULTIPLICATION OF FRACTIONS PART I

  6. Problem Solving Involving Sequences

COMMENTS

  1. Sets

    Consider the same example above. If the element 4 4 is removed from the set B B, solve for (i), (ii), (iii) as well. (i) Since there is no common elements in sets A A and B B, then A \cap B = \phi A∩B = ϕ or A \cap B = \ { \} A∩B = {}. (ii) Because the element 4 4 is no longer repeated, then A \cup B A ∪B remains the same.

  2. 1.5: Set Operations with Two Sets

    Learn how to perform various operations on two sets, such as union, intersection, complement, and difference, and how to represent them using Venn diagrams and set-builder notation. This section also introduces the concepts of subsets, partitions, and disjoint sets. Examples and exercises are provided to help you master the topic.

  3. Word Problems on Sets and Venn Diagrams

    Step 2 : Total number of students in the group : = 28 + 12 + 18 + 7 + 10 + 17 + 8 = 100. So, the total number of students in the group is 100. Problem 3 : In a college, 60 students enrolled in chemistry,40 in physics, 30 in biology, 15 in chemistry and physics,10 in physics and biology, 5 in biology and chemistry. No one enrolled in all the three.

  4. PDF Set Theory: Venn Diagrams for Problem Solving

    Create a Venn diagram with two sets. To do this, first draw two intersecting circles inside a rectangle. Be sure to label the circles accordingly. Now, work from the inside out. That is, begin by determining the number of cars in the intersection of the two sets. Since 6 out of the 50 cars needed no repairs, leaving.

  5. Set Operations

    Examples of Set Operations. Example 1: In a school, every student plays either football or soccer or both. It was found that 200 students played football, 150 students played soccer and 100 students played both. Find how many students were there in the school using the set operation formula.

  6. 9.2: Union, Intersection, and Complement

    9.2: Union, Intersection, and Complement. Commonly sets interact. For example, you and a new roommate decide to have a house party, and you both invite your circle of friends. At this party, two sets are being combined, though it might turn out that there are some friends that were in both sets. However, before we talk about multiple sets ...

  7. Practical problems on union and intersection of sets (basic)

    Practical problems on union and intersection of sets (basic) In a group of 50 students, 30 like to play football and 25 like to play cricket. Each student likes to play at least one of the two sports. How many students like to play both football and cricket? Learn for free about math, art, computer programming, economics, physics, chemistry ...

  8. Intersection and union of sets (video)

    The truth of a problem exists only in the real world, however you see a problem is a representation of that problem in your mind. ... The intersect, or n, would be {} because there isn't anything that's the same in both sets. The union, or U, would be {1,2,3,4,5,6,7,8}, not necessarily in numerical order. We don't repeat numbers in a union.

  9. 2.E: Basic Concepts of Sets (Exercises)

    Exercise 2.E. 8: Prove or disprove. Given subsets A, B, C of a universal set U, prove the statements that are true and give counter examples to disprove those that are false. P(A ∪ B) = P(A) ∪ P(B). P(A ∩ B) = P(A) ∩ P(B). P(Ac) = (P(A))c. P(A − B) = P(A) − P(B).

  10. PDF Chapter 1: Problem Solving: Strategies and Principles

    Slide 2 2.1. The Language of Sets • Specify sets using both listing and set-builder notation. • Understand when sets are well-defined. • Use the element symbol properly. • Find the cardinal number of sets. ... Section 1.1: Problem Solving Created Date: 1/3/2019 2:18:27 PM ...

  11. Operations on sets (intermediate) (practice)

    Choose 1 answer: Learn for free about math, art, computer programming, economics, physics, chemistry, biology, medicine, finance, history, and more. Khan Academy is a nonprofit with the mission of providing a free, world-class education for anyone, anywhere.

  12. Solving Word Problems Involving Sets

    Solving Word Problems Involving Sets - Solutions with step by step explanation. SOLVING WORD PROBLEMS INVOLVING SETS. Problem 1 : ... Problem 2 : A group of 20 college students were asked whether they are using the social net working sites. For that 8 said they use face book. 10 said they use twitter. 4 said they use both.

  13. Problems Involving Sets [Made EASY!]

    #Sets #SetsOperstions #VennDiagrams #WordProblemsInSets #ProblemsInvolvingSets #ProblemsInSetsAndVennDiagrams#SetsProblemSolving #SetsProblemSolvingWithSolut...

  14. elementary set theory

    Solving a Set Theory Problem Involving Intersections, Unions, and Complements Hot Network Questions Substitute HS Experiment for Synthesis/Decomposition of HgO

  15. Sets Questions

    Sets questions with solutions are given here for students to make them understand the concept easily. Practising these problems will help to go through the concept of sets theory.It is an important chapter for Class 11 students, hence we have given the questions based on the NCERT curriculum, with respect to the CBSE syllabus.

  16. PDF Quarter 1 Module 2: Problems Involving Sets

    Venn diagram is a principal way of showing sets diagrammatically. This method consists primarily of entering the elements of a set into a circle or circles. It can be used to solve word problems involving union and intersection of sets. In solving set operations using the Venn diagram, the following are the steps to be followed: Step 1.

  17. 1.6: Set Operations with Three Sets

    In this section, you will learn how to perform set operations with three sets, such as union, intersection, complement, and difference. You will also see how to use Venn diagrams to visualize the results of these operations and to verify the properties of sets. This section is part of the Contemporary Mathematics book by OpenStax, which covers various topics in applied mathematics.

  18. Problem Sets with Solutions

    Problem Sets with Solutions. pdf. 129 kB 18.05 Introduction to Probability and Statistics (S22), Class 01: Problem Solutions. pdf. 97 kB 18.05 Introduction to Probability and Statistics (S22), Class 02: Problem Solutions. pdf. 145 kB 18.05 Introduction to Probability and Statistics (S22), Class 03: Problem Solutions ...

  19. 6.3: The Union and Intersection of Two Sets

    Example \(\PageIndex{2}\): Union of Two sets. Consider the following sentence, "Find the probability that a household has fewer than 6 windows or has a dozen windows." Write this in set notation as the union of two sets and then write out this union. Solution. First, let A be the set of the number of windows that represents "fewer than 6 windows".

  20. Algebraic word problems

    Solving algebraic word problems requires us to combine our ability to create equations and solve them. To solve an algebraic word problem: Define a variable. Write an equation using the variable. Solve the equation. If the variable is not the answer to the word problem, use the variable to calculate the answer.

  21. PDF PRIMES Math Problem Set

    Problem G5. Let n be a positive integer and let S = f1;:::;ng. We choose three sub-sets A, B, C of S uniformly at random (from the 2n possible subsets), with replacement. (a)Find the expected value of jA\B \Cj. (b)Find the expected value of jA\BjjB \Cj. Problem G6. A robot starts at the point 0 on a number line. Thereafter, if it is at the ...

  22. An algorithm based on B-differentiable equations method for solving

    As shown in Fig. 4, the concrete beam has the dimensions of L×D×H = 16 m × 4 m× 4 m and is subjected to an axial displacement load on the right free side. The displacement constraints are applied along the normal direction on the faces A, B and C, respectively. Table 2 lists the comparisons of tensile and compressive damages between the proposed method and Abaqus.

  23. 7.6: Combinations- Involving Several Sets

    A standard deck of 52 playing cards has 4 suits with 13 cards in each suit. Each suit is associated with a color, either black (spades, clubs) or red (diamonds, hearts) Each suit contains 13 denominations (or values) for cards: nine numbers 2, 3, 4, …., 10 and Jack (J), Queen (Q), King (K), Ace (A). The Jack, Queen and King are called "face ...

  24. 2-step word problem: running (video)

    Well, this is essentially 9 plus 9 plus 9 plus 9. So we could just add up the 9's. 9 plus 9 is 18, plus 9 is 27, plus 9 is 36. So he ran a total of 36 kilometers. Now, that's not what they're asking us for. They're asking us for the number of kilometers Beth ran that week. And they tell us that she ran 15 fewer kilometers than Abe.