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Illustrative Mathematics (6-8 OUR Mathematics)

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Master Math 8 Homework with Morgan's Help!

Updated on Dec 06,2023

Master Math 8 Homework with Morgan's Help!

Table of Contents

Introduction, understanding balanced equations, balancing hangers and socks, activity: hanging blocks.

  • The Weight of Squares and Triangles

Solving Equations to Determine Square Weights

Exploring hanger balance with circles and triangles, problem solving: andre's family ages, writing equations for parallel lines.

In this article, we will Delve into the concept of balancing equations, specifically focusing on examples related to weights and hangers. We will explore various activities and problem-solving scenarios to better understand the principles behind balanced equations and their applications in real-life situations. By the end of this article, You will have a solid grasp of balancing equations and its relevance in everyday scenarios.

Before we dive into specific examples, it's important to understand the concept of balanced equations. In the realm of weight and hangers, a balanced equation refers to a state where the weight on each side of the hanger is equal. Just like a hanger needs equal weights on both sides to maintain balance, an equation requires equality between its expressions.

To grasp the concept of balancing equations, let's begin by examining the Scenario of balancing hangers using socks. Imagine having two socks hanging on a hanger. If one sock is HEAVIER than the other, the hanger will tilt towards the side with the heavier sock. This imbalance occurs because the weight on each side of the hanger is not equal.

However, it's crucial to note that the weight of an object does not solely depend on its size. In the case of the socks, the heavier sock may appear skinnier, but it could contain additional items like beans, making it heavier. The wetness of the sock from stepping in a puddle can also affect its weight. These factors highlight the importance of considering perplexity and burstiness in balancing equations.

Now, let's explore an activity called "Hanging Blocks." This activity provides a visual representation of a balanced hanger using squares and triangles. The key takeaway from this activity is that even though the squares and triangles are different shapes, the weight on both sides of the hanger remains balanced. This is because the weight on each side is proportional.

Elena, a participant in the activity, decides to remove two triangles from the left side and three triangles from the right side. The crucial question now is whether the hanger will remain balanced or tip towards one side. In this case, since Elena removed more triangles from one side than the other, the hanger will no longer be balanced. Consequently, it will tip towards the side with fewer triangles.

Additionally, the activity Prompts another question: If a triangle weighs one gram, what is the weight of a square? To determine this, we examine the equation representing the hanger's balance, which consists of three squares and two triangles on one side, and one square and five triangles on the other side. By setting up this equation, we can solve for the weight of one square, which is found to be equal to three over two grams or 1.5 grams.

Moving forward, let's explore a scenario involving different shapes and weights on hangers. Suppose a triangle weighs three grams, and a circle weighs six grams. The task at HAND is to determine the weight of a square on one hanger and the weight of a pentagon on another hanger.

To solve this problem, we need to set up the equations representing the weights on each hanger. For the hanger containing squares and triangles, we have three squares and two triangles on one side and one square and five triangles on the other side. By setting up this equation, we can solve for the weight of a square, which is calculated to be 3.75 grams.

However, when it comes to the hanger with circles and a pentagon, we encounter a challenge. The equation representing this hanger consists of twelve plus two pentagons on one side and six triangles plus six circles plus two pentagons on the other side. Unfortunately, this equation does not provide enough information to determine the weight of the pentagon. Hence, it remains undetermined.

Let's further analyze the concept of balancing hangers by considering their compositions. In this scenario, we have hangers comprised of circles and triangles. By observing the number of circles and triangles on each side, we can determine if the hanger will remain balanced or tilt towards the heavier side.

Suppose we have a hanger with three triangles and six circles on one side and an equal number of x variables on the other side. By analyzing the equation formed from this scenario, we can solve for x and determine that x is equal to 4 or 15/4. This knowledge allows us to calculate the weight of one square, which is found to be equal to -3 grams. However, since a negative weight is illogical, we conclude that this scenario is not possible.

In this problem-solving scenario, Andre presents a Puzzle related to the ages of his family members. Andre claims to be three years younger than his brother and two years older than his sister. Additionally, the age of his mother is one less than three times his brother's age. The sum of all the ages in the family adds up to 87.

To decipher the ages of Andre, his brother, sister, and mother, we need to construct equations Based on the given information. By assigning variables to each family member's age, we can Create a system of equations. Simplifying these equations, we find that Andre's age is 13, his brother's age is 16, his sister's age is 11, and his mother's age is 47.

Lastly, we explore the concept of parallel lines and how to write equations for lines that are parallel to each other. When dealing with parallel lines, it's essential to note that they have the same slope. The slope represents the rate of change between the x and y coordinates of the line.

To write equations for parallel lines, we'll examine two lines and determine their slopes using the given points. By calculating the slope based on the coordinates of the points, we can write equations for each line. In one form, the equation appears as y - y1 = m(x - x1), where m represents the slope and (x1, y1) represents the coordinates of a point on the line. In another form, the equation is y = mx + b, where m is the slope and b is the y-intercept.

By following these methods, we can write equations for two parallel lines and ensure that their slopes and points on the lines match accordingly.

Balancing equations plays a crucial role in various scenarios, from weights on hangers to determining family ages and writing equations for parallel lines. Understanding the principles behind balanced equations enables us to navigate real-life situations effectively. With the knowledge gained from this article, you are equipped to tackle complex problems involving balancing equations and Apply them in practical scenarios.

The above is a brief introduction to Master Math 8 Homework with Morgan's Help!

Let's move on to the first section of Master Math 8 Homework with Morgan's Help!

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  1. Math 8 3 2 Homework Help Morgan

    Illustrative Mathematics Grade 8 Open Up Resources OURUnit 3 Lesson 2More resources available at: mathhelp.cusd.com

  2. Math 8 3 3 Homework Help Morgan

    Illustrative Mathematics Grade 8 Open Up Resources OURUnit 3 Lesson 3More resources available at: mathhelp.cusd.com

  3. Mr. Morgan's Math Help

    Welcome to Mr. Morgan's Math Help Website! Below are links to different textbook series, grade level curriculum and the resources that have been put together to help you be successful in...

  4. Math 8 :: CUSD Math

    Lesson Summary & Homework Help. Lesson 1 - Number Puzzles. Lesson 1 . Morgan 8.4.1. Lesson 2 - Keeping the Equation Balanced. Lesson 2 . Morgan 8.4.2. Lesson 3 -Balanced Moves. Lesson 3. Intro to Equations with variables on both sides . Equations with variables on both sides: 20-7x=6x-6. Equations with variables on both sides . Morgan 8.4.3

  5. Math 8 Unit 2

    Math 8 Unit 2: Illustrative Mathematics Online Resources ... Khan Academy Online Practice. Class Notes. Lesson Summary & Homework Help. Lesson 1 - Projecting and Scaling. Lesson 1 : 8.2.1 Morgan. Lesson 2 - Circular Grid. Lesson 2 : 8.2.2 Morgan. Lesson 3 - Dilations with no Grid. Lesson 3 : 8.2.3 Morgan. Lesson 4 - Dilations on a Square ...

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    Lesson 13. Completing solutions to 2-variable equations. x-intercept of a line. Intercepts from an equation. Worked example: intercepts from an equation. Complete solutions to 2-variable equations. Intercepts from an equation. Quiz 3. 8.3.13 Morgan.

  7. OUR 8.2.3 Practice Problems • Teacher Guide

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  8. PDF 8th Grade Math

    2 Wednesday 6/3/20 Lesson 7 - Practice with Rational Bases Lesson 7 Complete 1-2 8.7.7 Morgan 8 7 7 CUSD Homework Help - Morgan Thursday Lesson 8 6/4/20 - Combining Bases Lesson 8 Complete 1-4 8.7.8 Morgan 8 7 8 CUSD Homework Help - Morgan 🎥Exponent properties with parentheses 📝Powers of products and quotients 📝Quiz 1 Friday Lesson ...

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    A rule that allows financial institutions to calculate simple interest using 360 days in a year is called. The Banker's rule. A = $8,000.00, r - 14.5%, t = 6 months. $7,459.21. In order to start a small business, a student takes out a simple interest loan for $4,000.00 for 3 months at a rate of 12.25%. The amount of interest is $122.50.

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  21. Lesson 8 3 Practice Answers

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  23. PDF MathLinks 8 Practice and Homework Book Chapter 2 Answers

    a) Yes, because 2 x 3 = 6, and 3 x 3 = 9. b) Yes, because 1 x 4 = 4, and 5 x 4 = 20. Answers may vary. 8' 12 6' 24 a) 15, because 8x 24, and 5 x 15 b) 15, because 1 x 5, and 3 x 15 Comparing Quantities: Answers may vary. For example: I would reuse the number line and number by tens. 142 7 Answers may vary. 28' 4' 14 a) 10 b) 3