eureka math grade 5 lesson 13 homework 5.1 answer key

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Eureka Math Grade 5 Module 5 Lesson 13 Answer Key

Engage ny eureka math 5th grade module 5 lesson 13 answer key, eureka math grade 5 module 5 lesson 13 problem set answer key.

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{5}{4}\) km × \(\frac{12}{5}\) km b. 16\(\frac{1}{2}\) m × 4\(\frac{1}{5}\) m c. 4\(\frac{1}{3}\) yd × 5\(\frac{2}{3}\) yd d. \(\frac{7}{8}\) mi × 4\(\frac{1}{3}\) mi Answer:

Therefore, 3 square kilometres

16 1/2 x 4 1/5

=  (16 x 4) + ( 16 x 1/5) + ( 4 x 1/2) x ( 1/2 x 1/5 )

= 64 + 16/5 + 2 + 1/10

Therefore, 69 3/10 square metres

4 1/3 x 5 2/3

4 x 5 + 4 x 2/3 + 5 x 1/3 + 1/3 x 2/3

= 20 +8/3 +5/3 +2/9

Therefore, 24 5/9 square yards

d.7/8 mi x 4 1/3 mi

= (7/8 x 4) + (7/8 x 1/3)

= 84/24 + 7/24

Therefore, 3 19/24 sq. mi

Question 2. Julie is cutting rectangles out of fabric to make a quilt. If the rectangles are 2\(\frac{3}{5}\) inches wide and 3\(\frac{2}{3}\) inches long, what is the area of four such rectangles? Answer:

Given, the measurements of the rectangles =

2 3/5 x 3 2/3

=( 2 x 3 ) + (2 x 2/3) + (3 x 3/5) + ( 3/5 x 2/3)

= 6 + 4/3 + 9/5 + 6/15

=6 + 3 8/15

= 9 8/15 square inches

Now, number of rectangles = 4

So, 4 x 9 8/15

= 36 + 2 2/15

Therefore, 38 2/15 square inches.

Given, the measurements of the lawn = 24 1/2 yd by 24 1/2 yd

The area of the lawn =

24 1/2 x 24 1/2

= (24 x 24 ) + (24 x 1/2 ) + (24 x 1/2) + ( 1/2 x 1/2)

= 576 + 12 +12 +1/4

=600 1/4 square yards

The area of the pool house = 16 square yards

The area of the pool =

7 1/2 yd x 2 1/2 yd

= 14 + 3 1/2 + 1 + 1/4

The area of sidewalk = 1 yd x 3 yd = 3 yd

Now, the amount of sod Howard needs to buy =

6001/4 – 16 – 18 3/4 – 3

= 581 1/4 – 18 2/4

= 580 5/4 – 18 3/4

= 562 1/2 square yards

Therefore, Howard need 562 1/2 square yards of sod.

Eureka Math Grade 5 Module 5 Lesson 13 Exit Ticket Answer Key

Find the area of the following rectangles. Draw an area model if it helps you. Question 1. \(\frac{7}{2}\) mm × \(\frac{14}{5}\) mm Answer:

7/2 mm x 4/5 mm

= 7/2 x 4/5

= 9 4/5 square mm

Question 2. 5\(\frac{7}{8}\) km × \(\frac{18}{4}\) km Answer:

5/8 km x 18/4 km

= 5/8 x 18/4

= 26 7/16 square kilometres.

Eureka Math Grade 5 Module 5 Lesson 13 Homework Answer Key

Question 1. Find the area of the following rectangles. Draw an area model if it helps you. a. \(\frac{8}{3}\) cm × \(\frac{24}{4}\) cm b. \(\frac{32}{5}\) ft × 3\(\frac{3}{8}\) ft c. 5\(\frac{4}{6}\) in × 4 \(\frac{3}{5}\) in d. \(\frac{5}{7}\) m × 6\(\frac{3}{5}\) m Answer:

8/3 cm x 24/4 cm

= 8/3 x 24/4

Therefore, 16 square centimetres

32/5 feet x 3 3/8

32/5 = 6 2/5

= 18 +  18/8 + 6/5 + 9/40

=  18 + 2 1/4 + 1 1/5 + 9/40

= 21 + 27/40

Therefore, 21 27/40 square feet

5 4/6 feet x 4 3/5 feet

( 5 x 4 ) + ( 5 x 3/5) + (4/6 x 4 ) + ( 4/6 x 3/5)

= 20 + 15/5 + 16/6 + 12/30

=20 + 3 + 8/3 + 2/5

= 25 +20/30 + 12/30

Therefore, 26 1/15 square inches

5/7 m x 6 3/5 m

= 5/7 x 6 3/5

=  30/7 + 15/35

= 4 2/7 + 3/7

Therefore, 4 5/7 square inches

Question 2. Chris is making a tabletop from some leftover tiles. He has 9 tiles that measure 3\(\frac{1}{8}\) inches long and 2\(\frac{3}{4}\) inches wide. What is the greatest area he can cover with these tiles? Answer:

Given, the measurements of the tiles =

3 1/8 x 2 3/4

= 6 + 9/4 + 2/8 + 3/32

= 6 +2 1/4 + 1/4 + 3/32

Now, the greatest area he can cover with 9 tiles=

= 9 x 8 19/32

= 72 + 191/32

= 72 +5 11/32

= 77 11/32 square inches.

Therefore, the greatest area he can cover = 77 11/32.

31 7/8 x 19 1/2

= ( 31 x 19) + ( 31 x 1/2 ) + (19 x 7/8 ) + ( 7/8 x 1/2)

= 589 + 31/2 + 133/8 + 7/16

= 589 + 15 1/2 + 16 5/8 + 7/16

= 620 + 1/2 + 5/8 + 7/16

= 630 + 8/16 + 10/16 + 7/16

= 620 25/16 square feet.

b. 13 3/5 feet x 11 3/4 feet

= ( 13 x 11) + ( 13 x 3/4 ) + (3/5 x 11 ) + ( 3/5 x 3/4)

= 143 + 9 3/4 + 6 3/5 + 9/20

=158 + 15/20 + 12/20 + 9/20

= 159 16/20

= 159 4/5 square feet

= 36 + 36/4

= 45 square feet

= 34 + 17/2

= 34 + 8 1/2

= 42 1/2 square feet

159 4/5 + 45 + 42 1/2

= 247 3/10 square feet

So, 621 9/16 – 247 3/10

= 384 21/80

Therefore, 384 21/80 square feet of carpeting is needed.

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5th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value and decimal fractions, unit 2: module 2: multi-digit whole number and decimal fraction operations, unit 3: module 3: addition and subtractions of fractions, unit 4: module 4: multiplication and division of fractions and decimal fractions, unit 5: module 5: addition and multiplication with volume and area, unit 6: module 6: problem solving with the coordinate plane.

EngageNY (Eureka Math) Grade 5 Module 1 Answer Key

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Texas Go Math Grade 4 Lesson 5.1 Answer Key Add and subtract parts of a whole

Refer to our Texas Go Math Grade 4 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 4 Lesson 5.1 Answer Key Add and subtract parts of a whole.

Essential Question

When con you odd or subtract ports of o whole? Answer: Explanation: When the denominators are same we can add or subtract

• fraction circles
• color pencils

A. Model the problem using fraction circles. Draw a picture of your model. Then write the sum.

Make connections

a. Are the wholes the same? Explain. Answer: No, Explanation: Both the shapes are different. The wholes are not same.

b. Does the sum \(\frac{1}{4}+\frac{1}{4}=\frac{2}{4}\) make sense in this situation? Explain. Answer: No. Explanation: Both the shapes are different The sum \(\frac{1}{4}+\frac{1}{4}=\frac{2}{4}\) make sense in this situation

Share and Grow

Use the model to write an equation.

Question 3. Multi-Step Sean has \(\frac{1}{5}\) of a cupcake and \(\frac{1}{5}\) of a large cake. a. Are the wholes the same? Explain. Answer: No, Explanation: The size cup cake and large cake are different.

b. Does the sum \(\frac{1}{5}+\frac{1}{5}\) = \(\frac{2}{5}\) make sense in this situation? Explain. Answer: No, Explanation: Equation is correct but not in this situation.

Use the model to solve the equation.

Problem Solving

H.O.T. Sense or Nonsense?

Question 7. H.O.T. Justify If there is \(\frac{4}{6}\) of a pie on a plate. what part of the pie is missing from the plate? Write an equation to justify your answer. Answer: \(\frac{4}{6}\) + \(\frac{2}{6}\) = 1 Explanation: \(\frac{2}{6}\) of the pie is missing from the plate

Daily Assessment Task

Fill in the bubble completely to show your answer. Use models to solve.

Question 8. At lunch yesterday, Ryan ate \(\frac{2}{6}\) of an apple and I ate \(\frac{2}{6}\) of the apple. Together, how much of the apple did we eat? (A) \(\frac{2}{6}\) (B) \(\frac{4}{6}\) (C) \(\frac{2}{12}\) (D) \(\frac{4}{12}\) Answer: B Explanation: \(\frac{2}{6}\) + \(\frac{2}{6}\) = \(\frac{4}{6}\) \(\frac{4}{6}\) they ate the apple.

Go Math Grade 4 Lesson 5.1 Answer Key Question 9. At the start of art class, Logan had \(\frac{7}{12}\) of a block of clay. After class, \(\frac{5}{12}\) of the block was left. What fraction of the block did Logan use during class? (A) \(\frac{7}{12}\) (B) \(\frac{12}{12}\) (C) \(\frac{5}{12}\) (D) \(\frac{2}{12}\) Answer: D Explanation: \(\frac{7}{12}\) – \(\frac{5}{12}\) = \(\frac{2}{12}\) Used the simplest form

Question 10. Multi-Step Samantha is mixing batter for muffins. She mixes \(\frac{2}{4}\) cup of flour and \(\frac{1}{4}\) cup of sugar, Then she adds \(\frac{1}{4}\) cup of milk. How much muffin batter has she mixed so far? (A) \(\frac{3}{8}\) cup (B) \(\frac{2}{4}\) cup (C) 1 cup (D) \(\frac{3}{4}\) cup Answer: C Explanation: \(\frac{2}{4}\) + \(\frac{1}{4}\)  + \(\frac{1}{4}\) = 1 Used the simplest form

TEXAS Test Prep

Texas Go Math Grade 4 Lesson 5.1 Homework and Practice Answer Key

Use the model to solve an equation.

Question 5. If there is \(\frac{6}{8}\) of a pizza on a plate, what part of the pizza is missing from the plate? Write an equation to justify your answer. Answer: \(\frac{2}{8}\) Explanation: 1 – \(\frac{6}{8}\) =  \(\frac{2}{8}\) \(\frac{2}{8}\)  part of the pizza is missing from the plate.

Question 6. If there is \(\frac{3}{8}\) of a pizza on a plate? what part of the pizza is missing from the plate? Write an equation to justify your answer. Answer: \(\frac{5}{8}\) Explanation: 1 – \(\frac{3}{8}\) =  \(\frac{5}{8}\) \(\frac{5}{8}\)  part of the pizza is missing from the plate.

Question 7. Maria is making cupcakes. She fills \(\frac{4}{12}\) of the cups with chocolate batter and \(\frac{7}{12}\) of the cups with vanilla batter. How many of the cups has Maria filled? Write an equation to justify your answer. Answer: \(\frac{11}{12}\) Explanation: \(\frac{4}{12}\) + \(\frac{7}{12}\)  = \(\frac{11}{12}\) Maria filled \(\frac{11}{12}\)  cups.

Lesson Check

Fill in the bubble completely to show your answer.

Question 11. Miranda made a poster for her science project. She filled \(\frac{3}{8}\) of the poster with photos and \(\frac{4}{8}\) of the poster with written information. how much space has she filled on Lier poster so far? (A) \(\frac{7}{8}\) (B) \(\frac{1}{8}\) (C) \(\frac{6}{8}\) (D) \(\frac{2}{8}\) Answer: B Explanation: \(\frac{3}{8}\) +  \(\frac{4}{8}\)  = \(\frac{7}{8}\) \(\frac{1}{8}\) space has she filled on lier poster so far

Go Math Grade 4 Lesson 5.1 Homework Answer Key Question 12. Multi-Step Carrie’s dance class learned \(\frac{1}{5}\) of a new dance on Monday, and \(\frac{2}{5}\) of the dance on Tuesday. What fraction of the dance is left for the class to learn on Wednesday? (A) \(\frac{4}{5}\) (B) \(\frac{3}{5}\) (C) \(\frac{2}{5}\) (D) \(\frac{1}{5}\) Answer: D Explanation: \(\frac{1}{5}\) + \(\frac{2}{5}\) = \(\frac{3}{5}\) 1 – \(\frac{3}{5}\) = \(\frac{1}{5}\) \(\frac{1}{5}\) fraction of the dance is left for the class to learn on Wednesday

Question 13. Multi-Step Mrs. Simon planted \(\frac{4}{12}\) of her flowers in her front yard, \(\frac{3}{12}\) of her flowers in her back yard, and \(\frac{2}{12}\) of her flowers on the side of her house. What fraction of her flowers has she planted so far? (A) \(\frac{2}{12}\) (B) \(\frac{9}{12}\) (C) \(\frac{3}{12}\) (D) \(\frac{10}{12}\) Answer: B Explanation: As the denominators are the same we can directly add the numerators \(\frac{4}{12}\) + \(\frac{3}{12}\) + \(\frac{2}{12}\) = \(\frac{9}{12}\)

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