case study motion in a straight line

Case Study Questions Class 11 Physics Motion in a Straight Line

Case study questions class 11 physics chapter 3 motion in a straight line, cbse case study questions class 11 physics motion in a straight line, case study – 1.


1	The complete length of the path between any two points is called distance.	Displacement is the shortest length between any two points.
2	Distance is a scalar quantity	Displacement is a vector quantity
3	For any given motion distance is always greater than or equal to displacement	For any given motion displacement is always smaller than or equal to distance.
4	The distance can only have positive values.	Displacement can be positive, negative, and even zero.

Case Study – 2

Case study – 3, case study – 4.

5) Show that V BA = – V AB

Case Study – 5

When an object is in motion, its position changes with time. But how fast is the position changing with time and in what direction? To describe this, we define the quantity average velocity. Average velocity is defined as the change in position or displacement ( △ x) divided by the time intervals ( △ t), in which the displacement occurs:

Average speed has obviously the same unit (m s –1 ) as that of velocity. But it does not tell us in what direction an object is moving. Thus, it is always positive (in contrast to the average velocity which can be positive or negative). If the motion of an object is along a straight line and in the same direction, the magnitude of displacement is equal to the total path length.

Average speed has SI unit of m/s. it is scalar quantity it has only magnitude and doesn’t have any direction. it is always positive.

Class 11 Physics Case Study Questions Chapter 3 Motion in a Straight Line

Post author: studyrate
Post published:
Post category: Class 11
Post comments: 0 Comments

In Class 11 Final Exams there will be Case studies and Passage Based Questions will be asked, So practice these types of questions. Study Rate is always there to help you. Free PDF Downloads of CBSE Class 11 Physics Chapter 3 Case Study and Passage-Based Questions with Answers were Prepared Based on the Latest Exam Pattern. Students can solve Class 11 Physics Case Study Questions Motion in a Straight Line to know their preparation level.

Join our Telegram Channel, there you will get various e-books for CBSE 2024 Boards exams for Class 9th, 10th, 11th, and 12th.

In CBSE Class 11 Physics Paper, There will be a few questions based on case studies and passage-based as well. In that, a paragraph will be given, and then the MCQ questions based on it will be asked.

Motion in a Straight Line Case Study Questions With Answers

Here, we have provided case-based/passage-based questions for Class 11 Physics Chapter 3 Motion in a Straight Line

Case Study/Passage-Based Questions

Case Study 1:

Where x2 and x1 are the positions of the object at times t2 and t1, respectively. The SI unit for velocity is m/s or m s–1, although km h–1 is used in many everyday applications. Like displacement, average velocity is also a vector quantity. Average speed is defined as the total path length traveled divided by the total time interval during which the motion has taken place:

Average speed = Total path length/ Total time interval.

The velocity at an instant is defined as the limit of the average velocity as the time interval Dt becomes infinitesimally small. In other words

Note that for uniform motion, velocity is the same as the average velocity at all instants. Instantaneous acceleration is defined in the same way as the instantaneous velocity

1) For uniform motion instantaneous velocity is the same as

a) Average velocity
b) Average acceleration
c) Instantaneous speed
d) None of these

Answer: a) Average velocity

2 If velocity is constant then

a) Acceleration is zero
b) Acceleration is positive
c) Acceleration is negative

Answer: a) Acceleration is zero

What is average velocity defined as? a) Total path length / Total time interval b) Displacement / Time interval c) Speed / Direction d) Time interval / Displacement

Answer: b) Displacement / Time interval

Which unit is used for velocity in everyday applications? a) m/s b) m s–1 c) km/h d) Both a and b

Answer:c) km/h

Which of the following is true about average speed? a) It is a vector quantity b) It can be negative c) It is always positive d) It describes the direction of motion

Answer: c) It is always positive

Case Study 2:

When an object is in motion, its position changes with time. So, the quantity that describes how fast is the position changes w.r.t. time and in what direction is given by average velocity. It is defined as the change in position or displacement (Δx ) divided by the time interval (Δt ) in which that displacement occurs. However, the quantity used to describe the rate of motion over the actual path is average speed. It is defined as the total distance traveled by the object divided by the total time taken.

(i) A 250 m long train is moving with a uniform velocity of 45 km/h. The time taken by the train to cross a bridge of length 750 m is (a) 56 s (b) 68 s (c) 80 s (d) 92 s

Answer: (c) 80 s

(ii) A truck requires 3 hr to complete a journey of 150 km. What is the average speed? (a) 50 km/h (b) 25 km/h (c) 15 km/h (d) 10 km/h

Answer: (a) 50 km/h

(iii) Average speed of a car between points A and B is 20 m/s, between B and C is 15 m/s and between C and D is 10 m/s. What is the average speed between A and D, if the time taken in the mentioned sections is 20s, 10s and 5s, respectively? (a) 17.14 m/s (b) 15 m/s (c) 10 m/s (d) 45 m/s

Answer: (a) 17.14 m/s

(iv) A cyclist is moving on a circular track of a radius of 40 m and completes half a revolution in 40 s. Its average velocity (in m/s) is (a) zero (b) 2 (c) 4π (d) 8π

Answer: (b) 2

Hope the information shed above regarding Case Study and Passage Based Questions for Class 11 Physics Chapter 3 Motion in a Straight Line with Answers Pdf free download has been useful to an extent. If you have any other queries about CBSE Class 11 Physics Motion in a Straight Line Case Study and Passage-Based Questions with Answers, feel free to comment below so that we can revert back to us at the earliest possible. By Team Study Rate

Class 11 english mcq questions with answers pdf hornbill, snapshots, mcq questions for class 11 with answers for all subjects, class 11 biology: case study of chapter 5 morphology of flowering plants pdf download, leave a reply cancel reply.

Save my name, email, and website in this browser for the next time I comment.

This site uses Akismet to reduce spam. Learn how your comment data is processed .

The Topper Combo Flashcards

Contains the Latest NCERT in just 350 flashcards.
Colourful and Interactive
Summarised Important reactions according to the latest PYQs of NEET(UG) and JEE

No thanks, I’m not interested!

CBSE Class 11 Physics Chapter 3 Motion in a Straight Line Study Materials

NCERT Solutions Class 11 All Subjects Sample Papers Past Years Papers

Kinematics: Motion in a Straight Line : Notes and Study Materials -pdf

Concepts of Kinematics: Motion in a Straight Line
Kinematics: Motion in a Straight Line Master File
Kinematics: Motion in a Straight Line Revision Notes
Kinematics: Motion in a Straight Line MindMap
NCERT Solution Kinematics: Motion in a Straight Line
NCERT Exemplar Solution Kinematics: Motion in a Straight Line
Kinematics: Motion in a Straight Line : Solved Example 1

Class 11 Physics Chapter 3 Motion in a Straight Line

Topics and Subtopics in Class 11 Physics Chapter 3 Motion in a Straight Line :


3	Motion in a Straight Line
3.1	Introduction
3.2	Position, path length and displacement
3.3	Average velocity and average speed
3.4	Instantaneous velocity and speed
3.5	Acceleration
3.6	Kinematic equations for uniformly accelerated motion
3.7	Relative velocity

Motion in a Straight Line Class 11 Notes Physics Chapter 3

• Introduction Motion is one of the significant topics in physics. Everything in the universe moves. It might only be a small amount of movement and very-very slow, but movement does happen. Even if you appear to be standing still, the Earth is moving around the sun, and the sun is moving around our galaxy. “An object is said to be in motion if its position changes with time”. The concept of motion is a re’ live one and a body that may be in motion relative to one reference system, may be at rest relative to another. There are two branches in physics that examine the motion of an object. (i) Kinematics: It describes the motion of objects, without looking at the cause of the motion. (ii) Dynamics: It relates the motion of objects to the forces which cause them. • Point Object If the length covered by the objects are very large in comparison to the size of the objects, the objects are considered point objects. • Reference Systems The motion of a particle is always described with respect to a reference system. A reference system is made by taking an arbitrary point as origin and imagining a co-ordinate system to be attached to it. This co-ordinate system chosen for a given problem constitutes the reference system for it. We generally choose a co-ordinate system attached to the earth as the reference system for most of the problems. • Total Path Length (Distance) For a particle in motion the total length of the actual path traversed between initial and final positions of the particle is known as the ‘total path length’ or distance covered by it. • Types of Motion In order to completely describe the motion of an object, we need to specify its position. For this, we need to know the position co-ordinates. In some cases, three position co-ordinates are required, while in some cases two or one position co-ordinate is required. Based on these, motion can be classified as: (i) One dimensional motion. A particle moving along a straight-line or a path is said to undergo one dimensional motion. For example, motion of a train along a straight line, freely falling body under gravity etc. (ii) Two dimensional motion. A particle moving in a plane is said to undergo two dimensional motion. For example, motion of a shell fired by a gun, carrom board coins etc. (iii) Three dimensional motion. A particle moving in space is said to undergo three dimensional motion. For example, motion of a kite in sky, motion of aeroplane etc. • Displacement Displacement of a particle in a given time is defined as the change in the position of particle in a particular direction during that time. It is given by a vector drawn from its initial position to its final position. • Factors Distinguishing Displacement from Distance —> Displacement has direction. Distance does not have direction. —> The magnitude of displacement can be both positive and negative. —> Distance is always positive. It never decreases with time. —> Distance ≥ | Displacement | • Uniform Speed and Uniform Velocity Uniform Speed. An object is said to move with uniform speed if it covers equal distances in equal intervals of time, howsoever small these intervals of time may be. Uniform Velocity. An object is said to move with uniform velocity if it covers equal displacements in equal intervals of time, howsoever small these intervals of time may be. • Variable Speed and Variable Velocity Variable Speed. An object is said to move with variable speed if it covers unequal distances in equal intervals of time, howsoever small these intervals of time may be. Variable Velocity. An object is said to move with variable velocity if it covers unequal displacements in equal intervals of time, howsoever small these intervals of time may be. • Average Speed and Average Velocity Average Speed. It is the ratio of total path length traversed and the corresponding time interval. Or The average speed of an object is greater than or equal to the magnitude of the average velocity over a given time interval. • Instantaneous Speed and Instantaneous Velocity Instantaneous Speed. The speed of an object at an instant of time is called instantaneous speed. Or “Instantaneous speed is the limit of the average speed as the time interval becomes infinitesimally small”. Instantaneous velocity The instantaneous velocity of a particle is the velocity at any instant of time or at any point of its path. or “Instantaneous velocity or simply velocity is defined as the limit of the average velocity as the time interval Δt becomes infinitesimally small.” • Acceleration The rate at which velocity changes is called acceleration. • Uniform Acceleration If an object undergoes equal changes in velocity in equal time intervals it is called uniform acceleration. • Average and Instantaneous Acceleration Average Accelerating. It is the change in the velocity divided by the time-interval during which the change occurs. Instantaneous Acceleration. It is defined as the limit of the average acceleration as the time-interval Δt goes to zero. • Kinematical Graphs The ‘displacement-time’ and the ‘velocity-time’ graphs of a particle are often used to provide us with a visual representation of the motion of a particle. The ‘shape’ of the graphs depends on the initial ‘co-ordinates’ and the ‘nature’ of the acceleration of the particle (Fig.) The following general results are always valid (i) The slope of the displacement-time graph at any instant gives the speed of the particle at that instant. (ii) The slope of the velocity-time graph at any instant gives the magnitude of the acceleration of the particle at that instant. (iii) The area enclosed by the velocity-time graph, the time-axis and the two co-ordinates at ,time instants t 1 to t 2 gives the distance moved by the particle in the time-interval from t 1 to t 2 . • Equations of Motion for Uniformly Accelerated Motion For uniformly accelerated motion, some simple equations can be derived that relate displacement (x), time taken (f), initial velocity (u), final velocity (v) and acceleration (a). Following equation gives a relation between final and initial velocities v and u of an object moving with uniform acceleration a: v = u + at • Suppose a body is projected vertically upward from a point A with velocity u. In some problems it is convenient to take the downward direction as positive, in such case all the measurements in downward direction are considered as positive i.e., acceleration will be +g. But sometimes we may need to take upward as positive and if such case acceleration will be -g. • Relative Velocity Relative velocity of an object A with respect to another object B is the time rate at which the object A changes its position with respect to the object B. —> The relative velocity of two objects moving in the same direction is the difference of the speeds of the objects. —> The relative velocity of two objects moving in opposite direction is the sum of the speeds of the objects. • IMPORTANT TABLES

Physics Concept Questions And Answers
Motion In A Straight Line Questions

Motion in a Straight Line Questions

What is motion in a straight line.

As we know, the change in position of a body with respect to time and its environment is called in motion. Therefore, as the name suggests, motion in a straight line is basically a linear motion in a certain straight line. Hence, motion in a straight line uses one dimension only.

Types of Linear Motion

The motion in a straight line, also entitled the rectilinear motion, is of two types:

Motion with zero acceleration and constant velocity is Uniform linear motion.
Motion with non-zero acceleration or flexible velocity is Non-Uniform linear motion.

As suggested by Newton’s first law of motion, an object will either be at rest or continue its motion with a uniform velocity in a straight line unless and until some external unbalanced force is applied to it. Hence, in the same way, linear motion is related to this law, as it is the most straightforward kind of one-dimensional motion.

General motion and linear motion should not confuse you because, as stated above, linear motion is a one-dimensional motion. Overall, the motion has both direction and magnitude; that is, an object’s velocity and position are described in vector quantities.

Uniform Motion in a Straight Line

If a body travels an equal amount of distance in an equal gap or interval of time in a straight line, then it is said to have uniform motion. In simple words, if the rate of change of the velocity of a body remains constant, then the body is said to have uniform acceleration.

Non-uniform Motion in a Straight Line

If the velocity of a body varies unequally in equivalent gaps or intervals of time, then the body is said to have a non-uniform motion. Hence, we can say that the rate of change of its velocity variates at different points of time during its motion.

Important Questions on Motion in a Straight Line

1) If the total displacement is divided by the total time taken, which of the following will be obtained?

b) Acceleration

c) Uniform velocity

d) Average Velocity

Correct Option: (d)

Explanation: Since velocity is said to be uniform when at every instant of time the velocity is equal to the average velocity, speed is the total distance divided by time, acceleration is obtained by velocity divided by time, and the average velocity is attained when total displacement is divided by the total time taken.

2) What kind of energy does a body possess when it is in the state of complete rest?

a) Kinetic energy

b) Potential energy

c) Thermal energy

d) Electrical energy

Correct Option: (b)

Explanation: There is no motion when a body is in a state of rest. Therefore, there will be no kinetic energy, and as we know, the sum of kinetic and potential energies is the total energy. Hence the total energy stored in the body will be potential energy.

3) Rectilinear motion is said to be what kind of motion?

a) Four dimensional

b) Three dimensional

c) One dimensional

d) Zero dimensional

Correct Option: (c)

Explanation: Since the linear motion, also entitled the rectilinear motion, happens in a straight line, it uses one dimension only. Therefore, rectilinear motion is one dimensional.

4) Which among the following forces can probably act on a body whose motion is in a straight line?

a) Force of friction

b) Tangential force

c) Magnetic force

d) Centrifugal force

Correct Option: (a)

Explanation: Since no surface in the world of physics is frictionless, whenever a body is in motion, the force of friction acts on it. And rest, all the given forces act on the body under some special conditions, like when it moves along a curve, and the magnetic force acts on a body when placed in a magnetic field.

5) Which among the following types of motion does not define the motion of the hand of a clock?

a) Rectilinear or linear

b) Periodic

c) Harmonic

d) Circular

Explanation: The motion of a hand of a clock is not a rectilinear motion, as it exhibits circular motion, because it moves in a circular manner. Furthermore, this motion also occurs periodically, so it is also a periodic motion too.

6) Calculate the velocity of a body that is vertically thrown upwards to a height of 20 m, and the time taken by the object to reach the highest point.

Distance travelled, s = 20 m

Final velocity, v = 0 m/s

g = -9.8 m/s 2

Using, v 2 −u 2 =2gs

u=19.79m/s , the velocity with which the object is thrown upwards.

Now, using,

= t = (v−u)/g = 2.02 sec

7) Define uniform motion in a straight line.

8) What is non-uniform motion in a straight line?

9) What is motion in a straight line and its types?

As we know, the change in position of a body with respect to time and its environment is called in motion. Therefore, as the name suggests, motion in a straight line is basically a linear motion in a certain straight line. Therefore, motion in a straight line uses one dimension only.

Uniform motion

Non-uniform motion

10) From the top of a multi-storey building, a ball is thrown vertically upwards with a velocity of 30m/s. In how much time the ball will hit the ground, if the height of the point from where the ball is thrown is 20 m from the ground? Take g=10ms −2 .

We can use v=u+at to calculate the time required by the ball to reach maximum height:

0=30+(−10) t

Since, s = ut+0.5at 2

= 30(3) +0.5(−10) (3) 2 = 45m

Therefore, for maximum height, the total distance is (45+20) m

Now, s = ut+0.5at 2

65=0+0.5(10) (t′) 2

t′ =3.60sec

Total time= 3.60 + 3= 6.60sec

Practice Questions

Define motion.
What are the three equations of motion?
Give examples of uniform and non-uniform motion.
What is circular motion?
What is uniform acceleration?

Motion in One Dimension |Concepts visualised | Distance and Displacement | NEET| Aanand Sir

Uniform Motion and Non Uniform Motion

Motion Graphs | Velocity-Time Graph and Displacement-Time Graph

Stay tuned to BYJU’S and Fall in Love with Learning !

PHYSICS Related Links

Register with BYJU'S & Download Free PDFs

Talk to our experts

1800-120-456-456

Motion in a Straight Line

Motion in a Straight Line - Explanation

In Physics, when the position of an object changes over a period of time is known as Motion. Mathematically the Motion is described in terms of displacement, distance, velocity , speed, acceleration, and time. By attaching the frame of reference, the Motion of a body is observed. Further, based on the change in position of the body relative to the frame, the Motion is measured.

Vedantu has always worked on the objective of providing the student with the best of content for their studies that not only enhances their knowledge level but also the eve of their understanding for this Vedantu has brought several other resources which are absolutely free of cost and can be downloaded easily in pdf format for future reference or can be viewed onLine to have a fair idea. Thus, it is advised to the students to review the website of Vedantu for all their needs of study under a single platform.

The students are also provided with access to free resources which can help them learn, revise, practice, and score good marks in the exam. Also, it is designed keeping in mind the current syllabus of the respective boards as per the curriculum.

What is Motion in a Straight Line?

The main aspects of Motion in a Straight Line is discussed in this course by including the difference between the distance and displacement, average velocity and speed, Acceleration along with the exercise of discussion. Further, solving the problem will grant students a holistic idea about the mechanics of Motion in a Straight Line.

The student should accumulate the knowledge and skills through this designed course. In each section, various ideas are explained in a simplified manner for the understanding of the student.

Types of Linear Motion

The two types of Linear Motion can be stated as follows:

Uniform Linear Motion

Non-Uniform Linear Motion

A body is known to be in uniform Motion if it covers equal distance in an equal Motion time-span. Here, the Motion is with zero Acceleration and constant velocity.

Whereas, a body is known as non-uniform if it covers an unequal distance in an equal period. It comprises non-zero Acceleration and variable velocity

Equations of Motion along a Straight Line

Calculus is the best way to derive the equation governing the Motion in a Straight Line. If the value of the three relations velocity-time, distance-time, and Acceleration-time is known in the mathematical form, the value of the others can be obtained by differentiation or integration

\[\frac{d}{dt}\] (distance) = velocity (v)

\[\frac{v}{vt}\] (velocity) = Acceleration (a)

There is another method known as the graphical method, which can be used if a precise mathematical relation cannot be obtained. The below figure shows the graphical representation Motion of a horse during a race and how the significant features of each graph are related to others.

Motion in a Straight Line Formulas

Constant Acceleration

This segment should be entitled "One-dimensional equations of Motion for constant Acceleration" for the sake of precision, as it will be a nightmare for a stylistic till let me begin this section with the following relations.

Velocity-time

During a uniform Acceleration , the Line of Motion is Straight; the longer the Acceleration greater will be the change in velocity. Hence the relation between velocity and time will be simple during the uniform Acceleration.

Enlarge ∆v to v − v₀ and condense ∆t to t.

a= (v−v₀) / t

Then resolve for v as a function of t.

v = v₀ + at

The second equation of Motion is written like a polynomial - a constant term (s 0 ), followed by a first-order term (v 0 t) and followed by a second-order term (½at 2 ). Since the maximum order is 2, it's more accurate to call it a quadratic.

∆s = v₀t + ½at²

The third equation of Motion - In this once again, the symbol s0 is the initial stance, and s is the position some time t later. If you prefer, you may pen the equation using ∆s — the change in stance, displacement, or distance as the situation merits.

v² = v₀² + 2a∆s

Indeed, a quick solution, it wasn't that difficult compared to the first two derivations. It, however, worked because Acceleration was constant in time and space.

Below are the formulas of Motion in a Straight Line:

s=ut+1/2at²

v² = u² + 2as

Linear Motion Definition

A one-dimensional gesture along a Straight Line and which can be described by using only one longitudinal dimension is known as Linear Motion or rectiLinear Motion. The Linear Motion is divided into two types: one is uniform Linear Motion with constant velocity or zero Acceleration, and the second one is non-uniform Linear Motion with a variety of velocity or non-zero Acceleration. The movement of a particle along the Line can be described by its position, which varies with time. For example, an athlete running 100m along a Straight track is known as Linear Motion.

It is one of the most basic Motions. As per Newton's first law of Motion, any object that doesn't feel any net force will continue to go in a Straight Line with a perpetual velocity until it is subjected to a net force. In everyday circumstances, external forces such as friction and gravity can cause a change in the direction of its Motion; hence its Motion cannot be described as Linear.

Important Questions for Motion in a Straight Line

Here are a few questions from the topic Motion in a Straight Line that will help the students to prepare well from the perspective of the final exams.

Out of the following examples of Motion, which of the body can be considered approximately a point object:

A tumbling beaker which is slipped off the edge of a table

A monkey sitting on the top of a smoothly cycling man who is on a circular track.

A railway carriage moving between two stations without jerks.

A spin ball of cricket that turns sharply on hitting the ground

The position-time (denoted by x-t) graphs for two children namely ‘A’ and ‘B’ who are returning from their school O to their homes P and Q respectively. Choose the correct answers in the brackets as follows;

(A/B) lives near to the school than (B/A)

(A/B) overtakes (B/A) on the road to school (once/twice)

(A/B) walks faster than (B/A)

A and B both reach their home at the (same/different) time

(A/B) starts walking from the school earlier than (B/A)

FAQs on Motion in a Straight Line

1. Which Body is Considered Approximately a Point Object?

A railway carriage is running without any jolts between two railway stations.

A monkey is resting on top of a man who is cycling effortlessly on a circular track.

A spinning cricket ball that turns steeply on hitting the cricket pitch.

A tumbling beaker that has tumbled off the side of a table

An object can be regarded as a point object if the size of the object is much lesser than the distance it moves in a reasonable duration of time.

The size of a carriage is minor as related to the distance between two stations. Therefore, the carriage can be regarded as a point-sized object.

The size of a monkey is minimal as compared to the size of a circular track. Therefore, the monkey can be deemed as a point-sized thing on the trail.

The size of a rotating cricket ball is equivalent to the distance through which it turns sharply on hitting the cricket pitch. Hence, the cricket ball cannot be deemed as a point object.

The size of a beaker is equivalent to the height of the table from which it slipped. Hence, the beaker cannot be deemed as a point object. Thus (a) and (b) are correct Solutions

2. Which Proper Entries are in the Brackets Below?

The position-time (x-t) graphs for two children A and B coming back from their school O to their homes, P and Q respectively are shown.

(A/B) lives nearer to the school than (B/A)

(A/B) departs from the school earlier than (B/A)

(A/B) walks quicker than (B/A)

A and B get home at the (same/different) time

(A/B) surpasses (B/A) on the road (once/twice).

As OP < OQ, A lives nearer to the school than B

For x = 0, t = 0 for A; while t has some fixed value for B. Therefore, Ahead starts from the school earlier than B

We know that velocity is equivalent to the slope of the x-t graph. Now, since the slope of the x-t graph of B is better than that of A; therefore, B walks quicker than A.

It is evident from the given graph that both A and B reach their homes at the same time.

The x-t graph meets only once for A and B. Also, B moves later than A, and his/her speed is more than that of A. Hence B surpasses A only once on the road.

3. Give an example of Motion in a Straight Line?

The topic Motion in a Straight Line is of utmost importance for the students as this topic forms one of the core concepts for this. Now, a body is said to move in a Straight Line when it keeps its positions changing with time. An Example of this could be A bus moving on a Straight road, a train moving on a Straight track, a runner running along a Straight track or a ball moving along a Straight path. All these are examples of Motion in a Straight Line which can be dealt with in detail from the chapter reading.

4. Explain the types of Motion in detail.

There are various types of Motion, some of which can be understood as below:

Rotatory Motion: This includes the physical Motion of an object which is spinning on an axis of its own. Also, when we say that a certain object has uniform rotational Motion, uniform circular Motion, or uniform rotary Motion, it means that the direction in which the object is moving does not change.

Oscillatory Motion: it is a Motion repeating itself and is referred to as the periodic or oscillatory Motion. The object in this Motion oscillates near to an equilibrium position because of a restoring force or torque.

Uniform circular: it is described as the movement of an object traveling on a circular path with constant speed.

RectiLinear Motion: The rectiLinear Motion is a Linear Motion where the direction of the velocity remains constant and the path is a Straight Line.

5. Where can I get the Motion in Straight Line topic notes?

The students are recommended to visit the website of Vedantu for the free download of Motion in a Straight Line topic notes. The notes are available for free which can be easily accessed by the students at the ease of their home. It is advised that the students must also go through the other resources available on Vedantu’s website which includes syllabus, sample papers, revision notes, worksheets, and other study material for use by the students. Thus, helping them to score high in the exams.

NCERT Study Material

PHYS101: Introduction to Mechanics

PHYS101 Study Guide

Unit 2: motion in a straight line, 2a. compare and contrast distance and displacement.

Define distance .
Define displacement .
Give an example of motion when the distance and displacement are the same .
Give an example of motion when the distance and displacement are different .

Distance describes how much an object has moved. It depends on how the object has moved, that is, the path the object took to get from the starting point to the ending point. The units for distance are length units, such as meters. Distance is called a scalar quantity . A scalar quantity describes the magnitude of the measurement, but not a specific direction.

Displacement describes the overall change in position of an object. It only depends on the starting and ending point of the object. It does not depend on the path taken to get between the two points. Like distance, the units for displacement are length units, such as meters. Displacement is a vector quantity , which means it has a magnitude and a specific direction associated with the measurement. So, the complete units for displacement also include a direction.

For an example, consider a four-story building. A person needs to travel on the elevator from the first to the third floor. To accomplish this, the person could take an elevator directly from the first floor to the third floor. In this case, the distance and displacement are the same, because the person went directly from the starting to the ending point.

However, this is not the only way the person could travel from the first to the third floor. They could accidentally hit the fourth floor button when they got on the elevator. In this case, they would travel from the first floor to the fourth floor, and back down to the third floor. In this instance, the displacement is still the first floor to the third floor. But, the distance is longer, because the person took a detour to the fourth floor.

2b. Define and distinguish between vector and scalar physical quantities

What is a scalar physical quantity ? Give an example of a scalar physical quantity.
What is a vector physical quantity ? Give an example of a vector physical quantity.
What is the major difference between scalar and vector physical quantities?

A scalar physical quantity is a measurement of quantity that has a magnitude (amount), but not a direction. Examples of scalar quantities include mass and temperature. These are scalar quantities because there is no direction associated with these measurements. In the previous learning outcome, we saw that distance is a scalar quantity because it has no direction associated with it.

A vector physical quantity is a measurement that has a magnitude (amount) and direction. Vectors are often depicted as an arrow. The length of the arrow shows the magnitude of the quantity, and the direction of the arrow shows the direction of the vector.

For simple one-dimensional systems, a vector is often written as the magnitude with a (+) or (-) to indicate direction. As we saw in the previous learning outcome, displacement is a vector quantity. Velocity is also a vector quantity, for example, 5.5 km/s east. This measurement shows the magnitude of the velocity (5.5 km/s) and the direction (east).

The major difference between scalar and vector quantities is that scalar quantities only have a magnitude and vector quantities have a magnitude and direction.

Review Vectors, Scalars, and Coordinate Systems .

2c. Explain the relationship between instantaneous and average values for physical quantities

What is an instantaneous value ? Give an example of an instantaneous value in physics.
What is an average value ? How is an average value calculated? Give an example of an average value in physics.

An instantaneous value is a value measured at a given instant, or time. For example, we can measure the velocity of an object at a given time as 5.5 km/s east. This is an instantaneous value because it was measured at a given instant. The velocity may not be constant over time, but at the instant it was measured, that was the velocity.

An average value is calculated over a period of time. For example, to calculate average speed, divide the distance traveled by time traveled. For example, if you drive 30 miles in two hours, your average speed is 15 miles/hour. However, as we know from driving, we rarely drive exactly the same speed for two hours. So, the instantaneous value of your speed could vary at any given time, but the average value is still 15 miles/hour.

2d. Compare and contrast speed and velocity

Define elapsed time and show how it is calculated.
Define average velocity and show how it is calculated.
Why is velocity a vector quantity ?
Define instantaneous speed and average speed .
Describe the velocity and speed for a given system.

Average velocity is the displacement divided by the elapsed time:

Here, the line you see above the v shows that it is an average quantity. This is common notation for average quantities. To calculate the average velocity, divide the change in displacement by the elapsed time.

Review equations 2.5 and 2.6 in Average Velocity .

The average velocity is a vector quantity. This is because displacement is a vector quantity. Because we calculate average velocity from a vector quantity, it itself is a vector quantity. This means that average velocity has a direction associated with it. In one dimensional systems, this means that the average velocity is written with a (+) or (-) sign, depending on the direction of the displacement.

Instantaneous speed is the magnitude of the instantaneous velocity, measured at a given time or instant. Unlike velocity, instant speed is a scalar quantity, so it does not have a direction associated with it. For example, if the instantaneous velocity of an object is -2 m/s, the object's instantaneous speed is 2 m/s.

The average speed of an object, however, is not simply the magnitude of the average velocity. We define the average speed of an object as the distance divided by the elapsed time. Recall from learning outcome 2a that distance is a scalar quantity that describes how much an object moved and that it can be very different from the vector displacement. Therefore, the average speed of an object is also a scalar quantity, and it can differ from the average velocity.

Take a look at Figures 2.10 and 2.11 . Figure 2.10 shows a diagram of the displacement and distance between a home and a store, which took 30 minutes total. For a roundtrip from home, to the store, and back home, the distance and displacement are quite different. The total distance traveled is 6 km (3 km to the store, and 3 km from the store back home). However, the total displacement is 0 because displacement is a vector. The person went +3 km to the store, and then -3 km back home. So, the total vector displacement is 0.

Based on the distance and displacement, we can calculate the average speed and velocity of the trip to the store and back. To determine the average speed, divide the distance by the elapsed time: 6 km/30 min = 2 km/min. However, to determine the average velocity, divide the displacement by the elapsed time: 0 km/30 min = 0 km/min. Figure 2.11 shows graphs of distance, average speed, and average velocity in this example.

2e. Solve one-dimensional kinematics problems

Define acceleration , instantaneous acceleration , and average acceleration .
Calculate displacement given average velocity and time.
Calculate final velocity given initial velocity, acceleration, and time.
Calculate the displacement of an accelerating object given acceleration and time.
Calculate the final velocity of an accelerating object given acceleration and time.

Because velocity is a vector, acceleration is also a vector quantity.

Instantaneous acceleration is acceleration measured at a specific instant in time. In most kinematic problems, we assume average acceleration is a constant value.

We need to derive the equations of motion before we can calculate displacement given average velocity and time.

Review equations 2.28 and 2.29 in Solving for Displacement and Final Position from Average Velocity when Acceleration is Constant :

Review an example of using these equations to solve for displacement, given average velocity and time, in Example 2.8: Calculating Displacement: How Far Does the Jogger Run? .

We need to derive the equations of motion before we can calculate the final velocity given initial velocity, acceleration, and time.

Review equation 2.35 in Solving for Final Velocity :

Review an example of using these equations to solve for final velocity given initial velocity, acceleration, and time in Example 2.9: Calculating Final Velocity: An Airplane Slowing Down after Landing .

To calculate the final displacement of an accelerating object, we first need to derive the equation necessary to solve these problems.

Review equation 2.40 in Solving for Final Position when Velocity is Not Constant :

Review an example using this equation to solve for final displacement given acceleration and time in Example 2.10: Calculating Displacement of an Accelerating Object: Dragsters .

To calculate the final velocity of an accelerating object, we need to derive the equation necessary to solve these problems.

Review the necessary equation 2.46 in Solving for Final Velocity when Velocity is Not Constant :

Review an example using this equation to solve for final velocity in an accelerating object in Example 2.11: Calculating Final Velocity: Dragsters .

Review a list of the important kinematics equations used in this section in the box Summary of Kinematics Equations .

Review more examples of using kinematics equations in Example 2.12: Calculating Displacement: How Far Does a Car Go When Coming to a Halt? and Example 2.13: Calculating Time: A Car Merges into Traffic .

2f. Describe the effects of gravity on an object in motion

Define gravity , free-fall , and acceleration due to gravity ?
How does air resistance affect the falling motion of objects on earth?

In reality, air resistance affects the acceleration of falling objects. Air resistance opposes the motion of an object in air, and causes falling lighter objects to accelerate less than heavier objects. This is why a feather falls to earth slower than a heavier object like a brick. If there was no air resistance, a feather and brick would fall to earth with the same acceleration due to gravity.

2g. Calculate the position and velocity of an object in free fall

Calculate the position and velocity of a falling object given initial velocity and time.
Use position and velocity data of an object in free fall to determine the acceleration due to gravity.

Review the relevant equations in the box Kinematics Equations for Objects in Free Fall where Acceleration = -g :

When calculating the position and velocity of a falling object, we need to consider two different conditions. First, the object can be thrown up and then enter free fall. For example, you could throw a baseball up and watch it fall back down.

Review this case in Example 2.14: Calculating Position and Velocity of a Falling Object: A Rock Thrown Upward . After reviewing the solution, pay special attention to the graphs in Figure 2.40 in the example.

The other case is when an object is thrown directly downward. For example, you could throw a baseball directly down from a second-floor window.

Review this case in Example 2.15: Calculating Velocity of a Falling Object: A Rock Thrown Down . After completing this example, review Figure 2.42, which compares what is happening in Examples 2.14 and 2.15. It is important to understand the difference between an object that is thrown up and enters free fall, versus an object that is directly thrown down.

2h. Draw and interpret graphs for displacement and velocity as functions of time, and determine velocity and acceleration from them

Define the dependent and independent variable in a graph .
Describe the graph of a straight line.
Analyze a graph of position versus time when acceleration is zero.
Analyze a graph of position versus time when acceleration is constant (not zero).

We define slope as:

The y–intercept is the point where the line crosses the y–axis of the graph.

Review Figure 2.46 .

An example of a linear graph is the graph of position versus time when acceleration is zero.

Review an example of this type of graph in Figure 2.47 . In this graph, we can determine the slope by picking two different points and calculating slope using the equation above. In this case, the unit for slope is m/s, which is the unit for velocity. Therefore, the slope for a graph of position versus time with zero acceleration is the average velocity of that object.

Review how to calculate the average velocity of an object from this type of graph in Example 2.17: Determining Average Velocity from a Graph of Position versus Time: Jet Car .

When acceleration is a non-zero constant, the graph of position versus time is no longer linear. Review an example of this type of graph in Figure 2.48 .

Note that while the position versus time graph is not linear, the velocity versus time graph is linear. In the position versus time graph, the slope at any given point is the instantaneous velocity of the object. The instantaneous slope can be determined by drawing tangent lines at various points along the graph, and using the tangent lines to determine slope.

Review tangent lines drawn in Figure 2.48 (a) .

To determine instantaneous velocity at a given time when acceleration is a non-zero constant, review Example 2.18: Determining Instantaneous Velocity from the Slope at a Point: Jet Car .

We can determine instantaneous velocity at multiple points along a position-time graph with constant non-zero acceleration. Then, we can plot velocity versus time, seen in Figure 2.48 (b) . We see that this is a linear graph. The slope has units of m/s 2 , which are acceleration units. Therefore, the slope of the velocity versus time graph is acceleration.

Unit 2 Vocabulary

Acceleration
Acceleration due to gravity
Air resistance
Average acceleration
Average speed
Average value
Average velocity
Dependent variable
Displacement
Displacement of an accelerating object
Equations of motion
Elapsed time
Final velocity of an accelerating object
Independent variable
Instantaneous acceleration
Instantaneous speed
Instantaneous value
Scalar physical quantity
Scalar quantity
Tangent line
Vector physical quantity
Vector quantity
Velocity of a falling object
Y–intercept

Gurukul of Excellence

Classes for Physics, Chemistry and Mathematics by IITians

Join our Telegram Channel for Free PDF Download

Conceptual Questions Based on Class 11 Physics Motion in A Straight Line

Last modified on: 1 year ago
Reading Time: 23 Minutes

Here we are providing conceptual questions for Class 11 Physics Motion in A Straight Line. Answers are also provided along with questions. So that students can read and understand the question. These questions are prepared by the subject experts. Students can read these conceptual questions based on Motion in A Straight Line for better topic clarity and therefore will be able to score better marks in their exam.

Conceptual questions based on class Motion in A Straight Line is given below. Go through each and every question to understand the topic clearly.

Q.1. Can a particle in one-dimensional motion have zero speed and a non-zero velocity?

Solution. No, it the speed is zero, the velocity will be necessarily zero.

Q.2. Can a body exist in a state of absolute rest or of absolute motion? Explain.

Solution: Absolute rest and motion are unknown. In order to know whether the position of an object changes with time or not, a point absolutely fixed in space has to be chosen as reference point. But no such point is known in the universe. The earth revolves around the sun, the entire solar system travels through our own galaxy, the Milkyway and clusters of galaxies move with respect to other clusters. So, no object in the universe is in a state of absolute rest.

As no object in the universe is at absolute rest, so the absolute motion cannot be realised. Only relative rest and relative motion can be realised.

Q.3. What do you mean by motion in one, two and three dimensions? Give examples of each type.

Solution: One dimensional motion. The motion of an object is said to be one dimensional if only one of the three coordinates specifying the position of the object changes with time. Here the object moves along a straight line. This motion is also called rectilinear or linear motion.

Examples of one dimensional motion:

(i) Motion of a train along a straight track.

(ii) Motion of a freely falling body.

Two dimensional motion. The motion of an object is said to be two dimensional if only two of the three coordinates specifying its position change with time.

Examples of two dimensional motion:

(i) Motion of planets around the sun.

(ii) A car moving along a zig-zag path on a level road. Three dimensional motion. The motion of an object is said to be three dimensional if all the three coordinates specifying its position change with time.

Q.4. Can the displacement be greater than the distance travelled by an object? Give reason.

Solution. No, the displacement of an object can be either equal to or less than the distance travelled by the object. This is because displacement is shortest distance between the initial and final positions of the object while distance travelled is the length of the actual path traversed by the object.

Q.5. Can a body have a constant velocity and still have a varying speed?

Solution. No, a body cannot have a constant velocity while having a Varying Speed. Whenever the speed changes, velocity’ also changes.

Q.6. What is meant by a point object? Give suitable examples.

Point object. If the position of an object changes by distances much greater than its own size in a reasonable duration of time, then the object may be regarded as a point object. When a point object moves, its rotational and vibrational motions may be ignored.

(i) Earth can be regarded as a point object for studying its motion around the sun.

(ii) A train under a journey of several hundred kilometres can be regarded as a point object.

Q.7. When does a cyclist appear to be stationary with respect to another moving cyclist?

Solution. When both the cyclists are moving in the same direction with the same velocity parallel to each other.

Q.8. Can an object have an eastward velocity while experiencing a westward acceleration?

Solution. Yes. A pendulum oscillating in east-west direction will have eastward velocity and westward acceleration in half cycle of its oscillation.

Q.9. Can the earth be regarded as point object when it is describing its yearly journey around the sun?

Solution. Yes, because size of the earth is much smaller than the distance from the sun.

Q.10. Can the direction of velocity of an object change, when acceleration is constant?

Solution. Yes. for an object thrown vertically upwards, the direction of velocity changes during its rise and fall. But acceleration acts always downwards and remains constant.

Q.11. When an observer is standing on earth, the trees and houses appear stationary to him. However, when he is sitting in a moving train, all these objects appear to move in backward direction. Why?

Solution. For the stationary observer, the relative velocity of trees and houses is zero. For the observer sitting in the moving train, the relative velocity of houses and trees is negative. So, these objects appear to move in backward direction.

Q.12. Is it possible for a body to be accelerated without speeding up or slowing down? If so, give an example.

Solution. Yes. An object in uniform circular motion is accelerating but its speed neither decreases nor increases.

Q.13. Can a body have zero velocity and still be accelerating?

Solution, yes. A body thrown vertically upwards has zero velocity at its highest point but has acceleration equal to the acceleration due to gravity.

Q.14. Two balls of different masses (one lighter and other heavier) are thrown vertically upward with same initial speed. Which one will rise to the greater height?

Solution. Both the balls will rise to the same heights. It is because, for a body moving with given initial velocity and acceleration, the distance covered by the body does not depend on the mass of the body.

Q.15. Can a body have a constant speed and still have a varying velocity?

Solution. Yes, a particle m uniform circular motion has a constant speed but varying velocity because of the change in its direction or motion at every’ point.

Q.16. Two balls of different masses (one lighter and other heavier) are thrown vertically upwards with the same speed. Which one will pass through the point of projection in their downward direction with the greater speed?

Solution. In case of motion under gravity, the speed with which a body returns back is always equal to the speed with which it is thrown up. Since expression for final speed does not involve mass, Both the balls will acquire the same speed.

Q.17. Even when rain is falling vertically downwards, the front screen of a moving car gets wet while the back screen remains dry. Why?

Solution. This is because the rain strikes the car in the direction of relative velocity of rain with respect to car.

Q.18. Can the speed of a body be negative?

Solution. No, because the speed of an object is the distance travelled per unit rune and distance travelled is never negative.

Q.19. Can the relative velocity of two bodies be greater than the absolute velocity of either body?

Solution. Yes. When two bodies move in opposite directions, the relative velocity of each is greater than the individual velocity of either body.

Q.20. Is the direction of acceleration same as the direction of velocity?

Solution. Not necessarily. If velocity increases, acceleration acts in the direction of velocity and if velocity decreases, then acceleration acts in the opposite direction of velocity.

Q.21. A car travelling with a velocity of 50 km/hr on a straight road is ahead of a motor-cycle travelling with a speed of 75 km/hr. How would the relative velocity be altered if motor cycle is ahead of car?

Solution. The relative velocity will remain same as it does not depend on the position of the two bodies.

Q.22. Is it possible that the brakes of a car are so perfect that the car stops instantaneously. If not, why?

Solution. No, it is not possible. In order to make velocity zero in an infinitesimally small interval of time, the car needs an infinite declaration which is not possible.

Q.23. Is it possible to have a constant rate of change of velocity when velocity changes Both in magnitude and direction? If yes, give one example.

Solution. Yes, in projectile motion, a body has uniform acceleration in the downward direction while its velocity changes Both in magnitude and direction at every point of its trajectory

Q.24. Under what condition is the average velocity equal to the instantaneous velocity?

Solution. When a body moves with a constant velocity, its average velocity over any time interval is same as is instantaneous velocity.

Q.25. Can we use the equations of kinematics to find the height attained by a body projected upwards with any velocity?

Solution. No. The equations of kinematics are applicable only so long as the acceleration is uniform. The acceleration due to gravity is uniform only near the surface of the earth.

Q.26. If the displacement of a body is zero, is the distance covered by it necessarily zero? Comment with suitable illustration.

Solution. No, it is not necessary that the distance covered by a body is zero when its displacement is zero. Consider a particle moving along a circular track of radius r. After the particle completes one revolution, its displacement is zero while the distance covered is 2πr.

Q.27. State in the following cases, whether the motion is one, two or three dimensional:

(i) a kite flying on a windy day,

(ii) a speeding car on a long straight high way,

(iii) a carrom coin rebounding from the side of the board,

(iv) an insect crawling on a globe, and

(v) a planet revolving around its star?

(i) three-dimensional, (ii) one-dimensional,

(iii) two-dimensional, (iv) two-dimensional,

(v) two-dimensional.

Q.28. Why is the speed, in general, greater than the magnitude of the velocity?

Solution. Because of the change in the direction of motion, the length of the path traversed by a body is generally greater than the magnitude of its displacement. So, speed is generally greater than the magnitude of velocity.

Q.29. Distinguish between distance and displacement.

	Distance	Displacement
1.	Distance is the length of the actual path traversed by a body, irrespective of its motion.	Displacement is the shortest distance between the initial and final positions of body in a given direction.
2.	Distance between two points may be same or different for different paths chosen.	Displacement between two given points is always same.
3.	It is a scalar quantity.	It is a vector quantity.
4.	Distance covered may be positive or zero.	Displacement covered may be positive, negative or zero.

Q.30. Distinguish between speed and velocity.

	Speed	Velocity
1.	It is the distance travelled by a body per unit time in any direction.	It is the distance travelled by a body per unit time in a fixed direction
2.	It is a scalar quantity.	It is a vector quantity.
3.	Speed may be positive or zero but never negative.	Velocity may be positive, negative or zero.

Conceptual Questions Based on Class 11 Physics

You may also like:, category lists (all posts).

All categories of this website are listed below with number of posts in each category for better navigation. Visitors can click on a particular category to see all posts related to that category.

Full Form (1)
Biography of Scientists (1)
Assertion Reason Questions in Biology (37)
Case Study Questions for Class 12 Biology (14)
DPP Biology for NEET (12)
Blog Posts (35)
Career Guidance (1)
Assertion Reason Questions for Class 10 Maths (14)
Case Study Questions for Class 10 Maths (15)
Extra Questions for Class 10 Maths (12)
Maths Formulas for Class 10 (1)
MCQ Questions for Class 10 Maths (15)
NCERT Solutions for Class 10 Maths (4)
Quick Revision Notes for Class 10 Maths (14)
Assertion Reason Questions for Class 10 Science (16)
Case Study Questions for Class 10 Science (14)
Evergreen Science Book Solutions for Class 10 (17)
Extra Questions for Class 10 Science (23)
HOTS for Class 10 Science (17)
Important Questions for Class 10 Science (10)
Lakhmir Singh Class 10 Biology Solutions (4)
Lakhmir Singh Class 10 Chemistry Solutions (5)
Lakhmir Singh Class 10 Physics Solutions (5)
MCQ Questions for Class 10 Science (20)
NCERT Exemplar Solutions for Class 10 Science (16)
NCERT Solutions for Class 10 Science (15)
Quick Revision Notes for Class 10 Science (4)
Study Notes for Class 10 Science (17)
Assertion Reason Questions for Class 10 Social Science (14)
Case Study Questions for Class 10 Social Science (24)
MCQ Questions for Class 10 Social Science (3)
Topicwise Notes for Class 10 Social Science (4)
CBSE CLASS 11 (1)
Assertion Reason Questions for Class 11 Chemistry (14)
Case Study Questions for Class 11 Chemistry (11)
Free Assignments for Class 11 Chemistry (1)
MCQ Questions for Class 11 Chemistry (8)
Very Short Answer Questions for Class 11 Chemistry (7)
Assertion Reason Questions for Class 11 Entrepreneurship (8)
Important Questions for CBSE Class 11 Entrepreneurship (1)
Assertion Reason Questions for Class 11 Geography (24)
Case Study Questions for Class 11 Geography (24)
Assertion Reason Questions for Class 11 History (12)
Case Study Questions for Class 11 History (12)
Assertion and Reason Questions for Class 11 Maths (16)
Case Study Questions for Class 11 Maths (16)
Formulas for Class 11 Maths (6)
MCQ Questions for Class 11 Maths (17)
NCERT Solutions for Class 11 Maths (8)
Case Study Questions for Class 11 Physical Education (11)
Assertion Reason Questions for Class 11 Physics (15)
Case Study Questions for Class 11 Physics (12)
Class 11 Physics Study Notes (5)
Concept Based Notes for Class 11 Physics (2)
Conceptual Questions for Class 11 Physics (10)
Derivations for Class 11 Physics (3)
Extra Questions for Class 11 Physics (13)
MCQ Questions for Class 11 Physics (16)
NCERT Solutions for Class 11 Physics (16)
Numerical Problems for Class 11 Physics (4)
Physics Formulas for Class 11 (7)
Revision Notes for Class 11 Physics (11)
Very Short Answer Questions for Class 11 Physics (11)
Assertion Reason Questions for Class 11 Political Science (20)
Case Study Questions for Class 11 Political Science (20)
CBSE CLASS 12 (8)
Extra Questions for Class 12 Biology (14)
MCQ Questions for Class 12 Biology (13)
Case Studies for CBSE Class 12 Business Studies (13)
MCQ Questions for Class 12 Business Studies (1)
Revision Notes for Class 12 Business Studies (10)
Assertion Reason Questions for Class 12 Chemistry (15)
Case Study Based Questions for Class 12 Chemistry (14)
Extra Questions for Class 12 Chemistry (5)
Important Questions for Class 12 Chemistry (15)
MCQ Questions for Class 12 Chemistry (8)
NCERT Solutions for Class 12 Chemistry (16)
Revision Notes for Class 12 Chemistry (7)
Assertion Reason Questions for Class 12 Economics (9)
Case Study Questions for Class 12 Economics (9)
MCQ Questions for Class 12 Economics (1)
MCQ Questions for Class 12 English (2)
Assertion Reason Questions for Class 12 Entrepreneurship (7)
Case Study Questions for Class 12 Entrepreneurship (7)
Case Study Questions for Class 12 Geography (18)
Assertion Reason Questions for Class 12 History (8)
Case Study Questions for Class 12 History (13)
Assertion Reason Questions for Class 12 Informatics Practices (13)
Case Study Questions for Class 12 Informatics Practices (11)
MCQ Questions for Class 12 Informatics Practices (5)
Assertion and Reason Questions for Class 12 Maths (14)
Case Study Questions for Class 12 Maths (13)
Maths Formulas for Class 12 (5)
MCQ Questions for Class 12 Maths (14)
Problems Based on Class 12 Maths (1)
RD Sharma Solutions for Class 12 Maths (1)
Assertion Reason Questions for Class 12 Physical Education (11)
Case Study Questions for Class 12 Physical Education (11)
MCQ Questions for Class 12 Physical Education (10)
Assertion Reason Questions for Class 12 Physics (16)
Case Study Based Questions for Class 12 Physics (14)
Class 12 Physics Conceptual Questions (16)
Class 12 Physics Discussion Questions (1)
Class 12 Physics Latest Updates (2)
Derivations for Class 12 Physics (8)
Extra Questions for Class 12 Physics (4)
Important Questions for Class 12 Physics (8)
MCQ Questions for Class 12 Physics (14)
NCERT Solutions for Class 12 Physics (18)
Numerical Problems Based on Class 12 Physics (16)
Physics Class 12 Viva Questions (1)
Revision Notes for Class 12 Physics (7)
Assertion Reason Questions for Class 12 Political Science (16)
Case Study Questions for Class 12 Political Science (16)
Notes for Class 12 Political Science (1)
Assertion Reason Questions for Class 6 Maths (13)
Case Study Questions for Class 6 Maths (13)
Extra Questions for Class 6 Maths (1)
Worksheets for Class 6 Maths (1)
Assertion Reason Questions for Class 6 Science (16)
Case Study Questions for Class 6 Science (16)
Extra Questions for Class 6 Science (1)
MCQ Questions for Class 6 Science (9)
Assertion Reason Questions for Class 6 Social Science (1)
Case Study Questions for Class 6 Social Science (26)
NCERT Exemplar for Class 7 Maths (13)
NCERT Exemplar for Class 7 Science (19)
NCERT Exemplar Solutions for Class 7 Maths (12)
NCERT Exemplar Solutions for Class 7 Science (18)
NCERT Notes for Class 7 Science (18)
Assertion Reason Questions for Class 7 Maths (14)
Case Study Questions for Class 7 Maths (14)
Extra Questions for Class 7 Maths (5)
Assertion Reason Questions for Class 7 Science (18)
Case Study Questions for Class 7 Science (17)
Extra Questions for Class 7 Science (19)
Assertion Reason Questions for Class 7 Social Science (1)
Case Study Questions for Class 7 Social Science (30)
Assertion Reason Questions for Class 8 Maths (7)
Case Study Questions for Class 8 Maths (17)
Extra Questions for Class 8 Maths (1)
MCQ Questions for Class 8 Maths (6)
Assertion Reason Questions for Class 8 Science (16)
Case Study Questions for Class 8 Science (11)
Extra Questions for Class 8 Science (2)
MCQ Questions for Class 8 Science (4)
Numerical Problems for Class 8 Science (1)
Revision Notes for Class 8 Science (11)
Assertion Reason Questions for Class 8 Social Science (27)
Case Study Questions for Class 8 Social Science (23)
CBSE Class 9 English Beehive Notes and Summary (2)
Assertion Reason Questions for Class 9 Maths (14)
Case Study Questions for Class 9 Maths (14)
MCQ Questions for Class 9 Maths (11)
NCERT Notes for Class 9 Maths (6)
NCERT Solutions for Class 9 Maths (12)
Revision Notes for Class 9 Maths (3)
Study Notes for Class 9 Maths (10)
Assertion Reason Questions for Class 9 Science (16)
Case Study Questions for Class 9 Science (15)
Evergreen Science Book Solutions for Class 9 (15)
Extra Questions for Class 9 Science (22)
MCQ Questions for Class 9 Science (11)
NCERT Solutions for Class 9 Science (15)
Revision Notes for Class 9 Science (1)
Study Notes for Class 9 Science (15)
Topic wise MCQ Questions for Class 9 Science (2)
Topicwise Questions and Answers for Class 9 Science (15)
Assertion Reason Questions for Class 9 Social Science (15)
Case Study Questions for Class 9 Social Science (19)
CHEMISTRY (8)
Chemistry Articles (2)
Daily Practice Problems (DPP) (3)
Books for CBSE Class 9 (1)
Books for ICSE Class 10 (3)
Editable Study Materials (8)
Exam Special for CBSE Class 10 (3)
H. C. Verma (Concepts of Physics) (13)
Study Materials for ICSE Class 10 Biology (14)
Extra Questions for ICSE Class 10 Chemistry (1)
Study Materials for ICSE Class 10 Chemistry (5)
Study Materials for ICSE Class 10 Maths (16)
Important Questions for ICSE Class 10 Physics (13)
MCQ Questions for ICSE Class 10 Physics (4)
Study Materials for ICSE Class 10 Physics (8)
Study Materials for ICSE Class 9 Maths (7)
Study Materials for ICSE Class 9 Physics (10)
Topicwise Problems for IIT Foundation Mathematics (4)
Challenging Physics Problems for JEE Advanced (2)
Topicwise Problems for JEE Physics (1)
DPP for JEE Main (1)
Integer Type Questions for JEE Main (1)
Integer Type Questions for JEE Chemistry (6)
Chapterwise Questions for JEE Main Physics (1)
Integer Type Questions for JEE Main Physics (8)
Physics Revision Notes for JEE Main (4)
JEE Mock Test Physics (1)
JEE Study Material (1)
JEE/NEET Physics (6)
CBSE Syllabus (1)
Maths Articles (2)
NCERT Books for Class 12 Physics (1)
NEET Chemistry (13)
Important Questions for NEET Physics (17)
Topicwise DPP for NEET Physics (5)
Topicwise MCQs for NEET Physics (32)
NTSE MAT Questions (1)
Physics (1)
Alternating Current (1)
Electrostatics (6)
Fluid Mechanics (2)
PowerPoint Presentations (13)
Previous Years Question Paper (3)
Products for CBSE Class 10 (15)
Products for CBSE Class 11 (10)
Products for CBSE Class 12 (6)
Products for CBSE Class 6 (2)
Products for CBSE Class 7 (5)
Products for CBSE Class 8 (1)
Products for CBSE Class 9 (3)
Products for Commerce (3)
Products for Foundation Courses (2)
Products for JEE Main & Advanced (10)
Products for NEET (6)
Products for ICSE Class 6 (1)
Electrostatic Potential and Capacitance (1)
Topic Wise Study Notes (Physics) (2)
Topicwise MCQs for Physics (2)
Uncategorized (138)

Test series for students preparing for Engineering & Medical Entrance Exams are available. We also provide test series for School Level Exams. Tests for students studying in CBSE, ICSE or any state board are available here. Just click on the link and start test.

Download CBSE Books

Exam Special Series:

Sample Question Paper for CBSE Class 10 Science (for 2024)
Sample Question Paper for CBSE Class 10 Maths (for 2024)
CBSE Most Repeated Questions for Class 10 Science Board Exams
CBSE Important Diagram Based Questions Class 10 Physics Board Exams
CBSE Important Numericals Class 10 Physics Board Exams
CBSE Practical Based Questions for Class 10 Science Board Exams
CBSE Important “Differentiate Between” Based Questions Class 10 Social Science
Sample Question Papers for CBSE Class 12 Physics (for 2024)
Sample Question Papers for CBSE Class 12 Chemistry (for 2024)
Sample Question Papers for CBSE Class 12 Maths (for 2024)
Sample Question Papers for CBSE Class 12 Biology (for 2024)
CBSE Important Diagrams & Graphs Asked in Board Exams Class 12 Physics
Master Organic Conversions CBSE Class 12 Chemistry Board Exams
CBSE Important Numericals Class 12 Physics Board Exams
CBSE Important Definitions Class 12 Physics Board Exams
CBSE Important Laws & Principles Class 12 Physics Board Exams
10 Years CBSE Class 12 Chemistry Previous Year-Wise Solved Papers (2023-2024)
10 Years CBSE Class 12 Physics Previous Year-Wise Solved Papers (2023-2024)
10 Years CBSE Class 12 Maths Previous Year-Wise Solved Papers (2023-2024)
10 Years CBSE Class 12 Biology Previous Year-Wise Solved Papers (2023-2024)
ICSE Important Numericals Class 10 Physics BOARD Exams (215 Numericals)
ICSE Important Figure Based Questions Class 10 Physics BOARD Exams (230 Questions)
ICSE Mole Concept and Stoichiometry Numericals Class 10 Chemistry (65 Numericals)
ICSE Reasoning Based Questions Class 10 Chemistry BOARD Exams (150 Qs)
ICSE Important Functions and Locations Based Questions Class 10 Biology
ICSE Reasoning Based Questions Class 10 Biology BOARD Exams (100 Qs)

✨ Join our Online NEET Test Series for 499/- Only for 1 Year

Discover more from Gurukul of Excellence

Subscribe now to keep reading and get access to the full archive.

Type your email…

CBSE Expert

CBSE Case Study Questions Class 11 Physics PDF Download

Are you a Class 11 Physics student looking to enhance your understanding and prepare effectively for your exams? Look no further! In this comprehensive guide, we present a curated collection of CBSE Case Study Questions Class 11 Physics that will help you grasp the core concepts of Physics while reinforcing your problem-solving skills.

CBSE 11th Standard CBSE Physics question papers, important notes, study materials, Previous Year Questions, Syllabus, and exam patterns. Free 11th Standard CBSE Physics books and syllabus online. Important keywords, Case Study Questions, and Solutions.

Class 11 Physics Case Study Questions

CBSE Class 11 Physics question paper will have case study questions too. These case-based questions will be objective type in nature. So, Class 11 Physics students must prepare themselves for such questions. First of all, you should study NCERT Textbooks line by line, and then you should practice as many questions as possible.

Chapter-wise Solved Case Study Questions for Class 11 Physics

Chapter 1: Physical World
Chapter 2: Units and Measurements
Chapter 3: Motion in a Straight Line
Chapter 4: Motion in a Plane
Chapter 5: Laws of Motion
Chapter 6: Work, Energy, and Power
Chapter 7: System of Particles and Rotational Motion
Chapter 8: Gravitation
Chapter 9: Mechanical Properties of Solids
Chapter 10: Mechanical Properties of Fluids
Chapter 11: Thermal Properties of Matter
Chapter 12: Thermodynamics
Chapter 13: Kinetic Theory
Chapter 14: Oscillations
Chapter 15: Waves

Class 11 students should go through important Case Study problems for Physics before the exams. This will help them to understand the type of Case Study questions that can be asked in Grade 11 Physics examinations. Our expert faculty for standard 11 Physics have designed these questions based on the trend of questions that have been asked in last year’s exams. The solutions have been designed in a manner to help the grade 11 students understand the concepts and also easy-to-learn solutions.

Class 11 Books for Boards

Why Case Study Questions Matter

Case study questions are an invaluable resource for Class 11 Physics students. Unlike traditional textbook exercises, these questions simulate real-life scenarios, challenging students to apply theoretical knowledge to practical situations. This approach fosters critical thinking and helps students build a deep understanding of the subject matter.

Let’s delve into the different topics covered in this collection of case study questions:

1. Motion and Gravitation

In this section, we explore questions related to motion, velocity, acceleration, and the force of gravity. These questions are designed to test your grasp of the fundamental principles governing motion and gravitation.

2. Work, Energy, and Power

This set of questions delves into the concepts of work, energy, and power. You will encounter scenarios that require you to calculate work done, potential and kinetic energy, and power in various contexts.

3. Mechanical Properties of Solids and Fluids

This section presents case study questions about the mechanical properties of solids and fluids. From stress and strain calculations to understanding the behavior of fluids in different situations, these questions cover a wide range of applications.

4. Thermodynamics

Thermodynamics can be a challenging topic, but fear not! This part of the guide offers case study questions that will clarify the laws of thermodynamics, heat transfer, and thermal expansion, among other concepts.

5. Oscillations and Waves

Get ready to explore questions related to oscillations, simple harmonic motion, and wave characteristics. These questions will deepen your understanding of wave propagation and the behavior of oscillatory systems.

6. Kinetic Theory and Laws of Motion

Kinetic theory and the laws of motion can be complex, but with our case study questions, you’ll find yourself mastering these topics effortlessly.

Discover a wide array of questions dealing with light, lenses, and mirrors. This section will improve your problem-solving skills in optics and enhance your ability to analyze optical phenomena.

8. Electrical Effects of Current

Electricity and circuits are fundamental to physics. The case study questions in this section will challenge you to apply Ohm’s law, Kirchhoff’s laws, and other principles in various electrical circuits.

9. Magnetic Effects of Current

Delve into the fascinating world of magnets and magnetic fields. This set of questions will strengthen your understanding of magnetic effects and their applications.

10. Electromagnetic Induction

The final section covers electromagnetic induction, Faraday’s law, and Lenz’s law. You’ll be presented with scenarios that test your ability to predict induced electromotive forces and analyze electromagnetic phenomena.

In conclusion, mastering Class 11 Physics requires a thorough understanding of fundamental concepts and their practical applications. The case study questions provided in this guide will undoubtedly assist you in achieving a deeper comprehension of the subject.

Remember, practice is key! Regularly attempt these case study questions to strengthen your problem-solving abilities and boost your confidence for the exams. Happy studying, and may you excel in your Physics journey!

Download India's best Exam Preparation App Now.

Key Features

Revision Notes
Important Questions
Previous Years Questions
Case-Based Questions
Assertion and Reason Questions

No thanks, I’m not interested!

Case Based Questions Test: Motion in a Straight Line - Grade 11 MCQ

10 questions mcq test - case based questions test: motion in a straight line, journey to a picnic spot: 2 friends started for a picnic spot, in two different cars. a drove his car at a constant velocity 60 km/h. b drove his car at a constant velocity 50 km/h. the velocity of b relative to a is v b – v a similarly, the velocity of object a relative to object b is v a – v b their friend c was supposed to wait at a point on the road for a lift. both of them forgot to pick up c. a and b reached the picnic spot within 2 hours and 2 hours 24 minutes respectively. what was the relative velocity of b relative to a.

– 10 km/h

– 55 km/h

velocity of B relative to A = V B - V A = 50 - 60 = -10

Journey to a picnic spot: 2 friends started for a picnic spot, in two different cars. A drove his car at a constant velocity 60 km/h. B drove his car at a constant velocity 50 km/h. The velocity of B relative to A is V B – V A Similarly, the velocity of object A relative to object B is V A – V B Their friend C was supposed to wait at a point on the road for a lift. Both of them forgot to pick up C. A and B reached the picnic spot within 2 hours and 2 hours 24 minutes respectively. What were the velocities of A and B relative to C?

A. 50 km/h, 60 km/h
B. 60 km/h, 50 km/h
C. Both 10 km/h
D. Both 55 km/h

60 – 0 = 60 km/h and the velocity of B relative to C was 50 – 0 = 50 km/h.

1 Crore+ students have signed up on EduRev. Have you?

Journey to a picnic spot: 2 friends started for a picnic spot, in two different cars. A drove his car at a constant velocity 60 km/h. B drove his car at a constant velocity 50 km/h. The velocity of B relative to A is V B – V A Similarly, the velocity of object A relative to object B is V A – V B Their friend C was supposed to wait at a point on the road for a lift. Both of them forgot to pick up C. A and B reached the picnic spot within 2 hours and 2 hours 24 minutes respectively. How the distance of the picnic spot can be found from the appropriate graph?

A. Length of the straight line is the required distance
B. Area under the line is the required distance
C. Half of the area under the line is the required distance
D. Distance of the origin from the end point of the line is the required distance

Tabu lives at A. He was supposed to go to his uncle’s house at B. A and B is connected by a straight road 5 km long. But that day the road was under repair. So, all the buses was following a diversion via C. A to B via C is 7 km. Moreover this route is congested. There is a traffic signal at C also.

Tabu got a seat just behind the driver. He noticed that the minimum reading in the speedometer was 15 km/h. But ultimately the bus took 1 hour to reach B. He could not understand the fallacy.

What is the distance and displacement of Tabu?

A. 7 km, 5 km
B. 5 km, 7 km
C. 5km, 5 km
D. 7km, 7 km

Speedometer measures

A. Average speed
B. Instantaneous speed
C. Distance traversed
D. None of the above

Which of the following graphs represents the motion of the bus if it covers AC distance at a speed 15 km/h, CB distance at a speed 20 km/h and total distance is covered in 1 hour including halt at traffic signal.

A. Figure (a)
B. Figure (b)
C. Figure (c)
D. Figure (d)

Journey to a picnic spot:

2 friends started for a picnic spot, in two different cars. A drove his car at a constant velocity 60 km/h. B drove his car at a constant velocity 50 km/h. The velocity of B relative to A is V B – V A Similarly, the velocity of object A relative to object B is V A – V B Their friend C was supposed to wait at a point on the road for a lift. Both of them forgot to pick up C. A and B reached the picnic spot within 2 hours and 2 hours 24 minutes respectively.

What was the relative velocity of A relative to B?

B. – 10 km/h
D. – 55 km/h

V A – V B = 60 – 50 = 10 km/h

Which one of the following shows the Velocity vs. Time Plot for A?

Why the speedometer reading was minimum 15 km/h, bus actual time required to cover 7 km was 1 hour?

A. Speedometer was erratic
B. Actual distance was more than 7 km.
C. Halt timing at the traffic signal, at the congested areas and at the bus stops are also to be taken into account.
D. Both (a) and (b)

If the bus followed ACB path and reached B in 1 hour, then the average speed of the bus would have been

None of the above

--> and get INR 200 additional OFF

Top Courses for Grade 11

Important Questions for Case Based Questions Test: Motion in a Straight Line

Case based questions test: motion in a straight line mcqs with answers, online tests for case based questions test: motion in a straight line.

cation olution

Join the 10M+ students on EduRev

Welcome Back

Create your account for free.

Forgot Password

NCERT Solutions for Class 11th: Ch 3 Motion In A Straight Line Physics

Ncert solutions for class 11th: ch 3 motion in a straight line physics science.

Contact Form

Skip to main content
Skip to secondary menu
Skip to primary sidebar
Skip to footer

Learn Insta

RD Sharma Solutions , RS Aggarwal Solutions and NCERT Solutions

Motion in a Straight Line Class 11 Important Extra Questions Physics Chapter 3

July 22, 2021 by Prasanna

Here we are providing Class 11 Physics Important Extra Questions and Answers Chapter 3 Motion in a Straight Line. Important Questions for Class 11 Physics with Answers are the best resource for students which helps in Class 11 board exams.

Class 11 Physics Chapter 3 Important Extra Questions Motion in a Straight Line

Motion in a straight line important extra questions very short answer type.

The Velocity Calculator is a handy physics tool to quickly get your answer.

Question 1. Can a moving body have relative velocity zero with respect to another body? Give an example. Answer: Yes, two trains running on two parallel tracks with the same velocity in the same direction.

Free Projectile Motion Calculator – calculate projectile motion step by step.

Question 2. Can there be motion in two dimensions with acceleration in only one dimension? Answer: Yes, projectile motion.

Question 3. Is it true that a body is always at rest in a frame that is fixed to the body itself? Answer: Yes.

Question 4. Tell under what condition a body moving with uniform velocity can be in equilibrium? Answer: When the net force on the body is zero.

Question 5. What does the speedometer records: the average speed or the instantaneous speed? Answer: It records (or measures) the instantaneous speed.

Question 6. Can an object be accelerated without speeding up or slowing down? Give examples, Answer: Yes, circular motion.

Question 7. Is it possible to have the rate of change of velocity constant while the velocity itself changes both in magnitude and direction? Give an example. Answer: Yes, in projectile motion.

Question 8. Which motion is exactly represented by Δs = vΔt? Answer: It Represents motion with uniform velocity.

Question 9. In which frame of reference is the body always at rest? Answer: The body is always at rest in the frame attached to it i. e. inertial frame of reference.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 1

Question 12. What is meant by a point object in Physics? Answer: An object is said to be a point object if its dimensions are very small as compared to the distance covered by it.

Question 13. The displacement of a body is zero. Is the distance covered by it is necessarily zero? Answer: No.

Question 14. Which of the velocity or speed is measured by the speedometer of a vehicle? Answer: Speed.

Question 15. Can you think of a situation where a body falling under gravity has constant velocity? Give example. Answer: Yes, the terminal velocity of a body.

Question 16. Give an example of a motion which even though is accelerated motion yet it is called uniform motion. Answer: Uniform circular motion.

Question 17. How many-dimensional motion does the following have? (a) Train moving fast on its track. Answer: One dimensional motion.

(b) A lizard moving on a wall in a room. Answer: Two-dimensional motion.

(d) Bee flying in a closed room. Answer: Three-dimensional motion.

Question 18. When is the average velocity over an interval of time becomes equal to instantaneous velocity? Answer: When the velocity is constant.

Question 19. A coolie carries a bag of luggage from one side of a platform to another side on the same platform. How far vertically the load is shifted? Answer: Zero.

Question 20. The displacement of a body is proportional to the square of time along a straight line. Is the body moving with constant velocity or constant acceleration? Answer: It is moving with constant acceleration.

Question 21. When the train in which you are sitting starts moving by the side of another train without jerks, you find that the other train is moving but when you look to the platform you find that your train is moving. Name the phenomenon responsible for such a motion. Answer: Relative velocity is the phenomenon responsible for such a motion.

Question 22. Under what condition the magnitude of the average velocity of a particle is equal to the average speed? Answer: The magnitude of the average velocity of a particle is equal to the average speed if it moves with constant velocity.

Question 23. Two particles A and B are moving along the same straight line with B being ahead of A. Velocities remaining unchanged, what would be the effect on the magnitude of relative velocity if A is ahead of B? ’ Answer: The magnitude of the relative velocity will remain the same i.e. no effect on its magnitude.

Question 24. Define the speed of the object. Answer: The speed of an object is defined as the distance covered by it per unit of time.

Question 25. Why the speed of an object cannot be negative? Answer: The speed of an object cannot be negative because the distance can never be negative.

Question 26. Can a body have zero velocity and still accelerating? Answer: Yes.

Question 27. Can the direction of the velocity of a body change, when acceleration is constant? Answer: Yes.

Question 28. Is the acceleration of a car is greater when the accelerator is pushed to the floor or when the brake pedal is pushed hard? Answer: The acceleration of the car is greater when the brake pedal is pushed hard because the car comes to rest suddenly i. e. the rate of change of velocity of the car is large in this case, so the acceleration.

Question 29. The displacement is given by x = 2 + 4t + 5t 2 . Find the value of instantaneous acceleration. Answer: a = \(\frac{\mathrm{d}^{2} \mathrm{x}}{\mathrm{dt}^{2}}\) = 10

Question 30. A stone is thrown vertically upwards from the surface of Earth. What is the direction of the velocity and acceleration of the stone? (a) on its upward motion Answer: Velocity is vertically upward and acceleration is vertically downward.

(b) on its downward motion? Answer: Both velocity and acceleration are vertically downward.

Question 31. Can Earth be regarded as a point object if only the orbital motion of Earth around the Sun is considered? Why? Answer: Yes. This is because the size of Earth is very small as compared to the size of the orbit of the Earth around the Sun.

Question 32. The motion of two persons is shown by two straight lines on a displacement time graph intersecting each other at a certain point. What information do you get from the point of intersection? Answer: This means that the two persons cross each other at a certain place at a given instant of time.

Question 33. Following two equations represents the x – t relation for the motion of an objects. x (t) = x(0) + v(0)t + \(\frac{1}{2}\) at 2 and x(t) = v(0)t + \(\frac{1}{2}\) at 2 What is the difference between them? Answer: The first equation is a more general form of motion as it contains information regarding the initial position of the object.

Question 34. Can the speed of a body change if its velocity is constant? Why? Answer: No, the speed of a body cannot change if its velocity is constant which means that both the magnitude and direction of velocity do not change. The magnitude of velocity is speed, so speed cannot change.

Question 35. If the instantaneous velocity of a particle is zero, will its instantaneous acceleration be necessarily zero? Answer: No.

Question 36. What is the shape of the displacement time graph of a particle having an average velocity equal to its instantaneous velocity? Answer: In this case, the velocity is uniform, so the x – t graph is a straight line.

Question 37. Can there be a two-dimensional motion with acceleration in one dimension only? Give example. Answer: Yes, a projectile motion which is two-dimensional one has acceleration only in one dimension i.e. vertically downward.

Question 38. Under what condition will the distance and displacement of a moving object will have the same magnitude? Answer: The distance and displacement of a moving object will have the same magnitude when it is moving with uniform velocity along a straight line.

Question 39. Under what condition an object in motion cannot be considered a point object? Answer: A moving object cannot be considered as a point object if its size is not negligible as compared to the distance travelled by it.

Question 40. Define a point object. Answer: It is defined as an object having dimensions (length, breadth, thickness etc.) very small as compared to the distance covered by it.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 3

Question 42. Explain why the graph in the above question is not possible? Answer: This is because the speed for a given time is negative and speed is always positive.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 4

Question 44. What happens to kinematic equations under time reversal? Answer: The kinematic equations of motion don’t change in the form under time reversal i.e. if t is replaced by -t.

Question 45. What happens to the uniform motion of a body when it is given an acceleration at right angles to its motion? Answer: The body will come in a circular motion when it is given an acceleration at right angles to its motion.

Question 46. To deal with physical phenomena, we consider objects even as big as Sun a point objects. Can you name physical phenomena in which Earth cannot be taken as a point object? Answer: The occurrence of solar or lunar eclipse does not allow Earth to be taken as a point object otherwise the phenomena cannot be explained.

Question 47. The average velocity of a body moving with uniform acceleration is given by \(\frac{1}{2}\) (u + v). Ii the acceleration changes from point to point can the average velocity be still given by this expression? Give reason. Answer: No, the average velocity cannot be given by \(\frac{1}{2}\) (u + v) in case the acceleration varies from point to point i.e. if it is not uniform. This is because the slope of the v-t graph does not remain the same at all points.

Question 48. Acceleration is defined as the rate of change of velocity. Suppose we call the rate of change of acceleration SLAP. Then (i) What is the unit of SLAP. Answer: SLAP = Acceleration/time (By definition).

∴ Its unit will be = \(\frac{\mathrm{ms}^{2}}{\mathrm{~s}}\) = ms -3 .

(ii) How can you calculate instantaneous SLAP? Answer: Average SLAP = \(\frac{\Delta \mathrm{a}}{\Delta \mathrm{t}}\)

Question 49. Why is the time stated twice in stating acceleration? Answer: Since acceleration is the double rate of change of displacement

i. e. a = \(\frac{\mathrm{d}^{2} \mathrm{x}}{\mathrm{dt}^{2}}\), so time is stated twice in stating acceleration.

Question 50. Separate the following in one, two and three-dimensional motion : (a) a kite flying on a windy day. (b) an insect crawling on a globe. (c) a carom coin rebounding from the side of the board, (d) a planet revolving around its star. (e) the motion of a boat. (f) the motion of a dropped body. (g) the motion of a tennis ball. (h) a charged particle moving under an electric field. (i) movement of a saw while cutting wood. (j) molecular motion. (k) a charged particle moving under a magnetic field. Answer:

One dimensional motion : (e), (f), (i)
Two dimensional motion : (b), (c), (d), (g), (h), (k).
Three dimensional motion : (a), (j).

Motion in a Straight Line Important Extra Questions Short Answer Type

Question 1. Prove that the average velocity of a particle over an interval of time is either smaller than or equal to the average speed of the particle over the same interval. Answer: Average velocity is defined as the ratio of the total displacement to the total time. Average speed is defined as the ratio of the total distance to the total time. Since displacement is less than or equal to the distance, therefore the average velocity is less than or equal to the average speed.

Question 2. Two trains each of the length 109 m and 91 m are moving in opposite directions with velocities 34 km h -1 and 38 km h -1 respectively. At what time the two trains will completely cross each other? Answer: Let l 1 , l 2 be the lengths of the two trains. v 1 , v 2 be their velocities respectively.

∴ l 1 = 109m, l 2 = 91 m, v 1 = 34kmh -1 , v 2 = 38kmh -1 . As the trains are moving in opposite directions so relative velocity of the trains is given by v 1 – (- v 2 ) = v 1 + v 2 = 34 + 38 = 72 kmh -1 = 72 × \(\frac{5}{18}\) = 20 ms -1

Total distance to be covered by the two trains in crossing each other = l 1 + l 2 = 109 + 91 = 200 m

If t be the time taken in crossing, then t can be calculated using the relation x = vt or t = \(\frac{200}{20}\) = 10s

Question 3. Ambala is at a distance of 200 km from Delhi. Ram sets out from Ambala at a speed of 60 km h -1 and Sham set out at the same time from Delhi at a speed of 40 km h -1 . When will they meet? Answer: S = 200 km. Let VR and vs be the speeds of Ram and Sham respectively moving in opposite directions. ∴ v R = 60 kmh-1, v S = 40 kmh -1 .

∴ Relative velocity of Ram w.r.t. Sham is V RS = V R – (- V S ) = V R + V S = 60 + 40 = 100 kmh -1

If t = time after which they will meet, then t = time taken in covering 200 km distance with V RS i.e. t = \(\frac{200}{v_{\mathrm{RS}}}=\frac{200 \mathrm{~km}}{100 \mathrm{kmh}^{-1}}\) = 2h.

∴ Time after which they meet = 2h.

Question 4. A car travelling at a speed of 60 km h -1 on a straight road is ahead of a scooter travelling at a speed of 40 km h -1 . How would the relative velocity be altered if the scooter is ahead of the car? Answer: v c = speed of car = 60 kmh -1 v s = speed of scooter = 40 kmh -1 v cs = relative velocity of car w.r.t. scooter = v c – v s = 60 – 40 = 20 kmh -1

Similarly vsc = relative velocity of scooter w.r.t. car = v s – v c = 40 – 60 = – 20 kmh- -1

Thus we conclude that the magnitude of the relative velocity is the same in both cases but the direction of relative velocity is reversed if the scooter is ahead of the car.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 6

Question 6. A ball is thrown vertically upward with a velocity of 20 ms -1 . It takes 4 seconds to return to its original position. Draw a velocity-time graph for the motion of the ball and answer the following questions: At which point P, Q, R, the stone has : (a) reached its maximum height. (b) stopped moving? Answer: Let P represent the initial position at the time when the ball is thrown vertically upward. Q represents the highest point reached by the ball. R represents the original position of the ball after 4 seconds.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 7

(b) The stone has stopped moving at point Q because at Q, v = 0.

Question 7. “It is the velocity and not the acceleration which decides the direction of motion of a body.” Justify this statement with the help of a suitable example. Answer: The direction of velocity is always in the direction of motion of the body whereas the direction of acceleration may or may not be in the direction of motion of the body. Thus we conclude that it is the velocity that decides the direction of motion of the body.

Example: When a ball is thrown vertically upwards, the direction of motion of the ball and velocity is the same i.e. vertically upwards. On the other hand, the acceleration due to gravity on the ball acts vertically downwards i.e. opposite to the direction of motion of the ball.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 8

If θ be the direction of vAB w.r.t. uA, Then tan θ = \(\frac{u_{A}}{v_{A B}}=\frac{u_{A}}{\sqrt{u_{A}^{2}+u_{B}^{2}}}\) …(2)

Thus, equations (1) and (2) give the magnitude and direction of relative velocity of A w.r.t. B.

Question 9. A draw velocity-time graph for a body which (i) accelerates uniformly from rest, Answer: The required velocity-time graph is shown in Fig. here

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 9

(ii) then moves with a uniform velocity and Answer: AB part of the graph represents motion with uniform velocity.

(iii) finally retarded uniformly. Answer: BC part of the graph represents motion with uniform retardation of the body.

Question 12. Draw the velocity-time graph for an object moving with uniform velocity. What does it show for t < 0? Answer: As the object moves with uniform velocity, the magnitude and direction of its velocity remain the same at all points of its path. Thus v – t graph’ is a straight line parallel to the time axis as shown in Fig. here.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 13

Question 14. Distinguish between one, two and three-dimensional motion. Answer: The motion of an object along a straight line in a fixed direction is called one-dimensional motion.

The motion of an object in a plane is called two-dimensional motion
The motion of an object in space is called three-dimensional motion

Question 15. A ball thrown upward reaches a height and comes bad downward. Out of the following statements, which one is true for displacement, velocity and acceleration. (a) It varies continuously but never changes the sign. (b) It varies continuously with the maximum, in the beginning, being zero at the top. (c) It remains constant throughout the course of the journey. (d) It only changes the sign when the ball is at the top. Answer:

Statement (a) is true for displacement as it varies from starting
Statement (b) is true for velocity as it is maximum at the time o projecting the ball and becomes zero at the highest point i.e. top.
Statement (c) is true for acceleration as it is always constant throughout the course of the journey and is equal to ‘g’.

Question 16. Derive the expression for the time taken by a body dropped from a height h to reach at Earth. Answer: Here, initial velocity, u = 0 acceleration, a = g distance covered, S = h

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 15

Question 17. In which of the following cases, the body may be considered a point object: (a) A railway carriage moving without jerks between two stations. (b) A monkey sitting on the shoulder of a cyclist moving smoothly in a circular track. 1 A beaker tumbling down the edge of a table, A spinning cricket ball that turns sharply on hitting the ground. Answer: (a) and (b) as the distance moved by the bodies is much larger; the size of the body.

Question 18. What do you understand by positive and negative time? Answer: The origin of time is called zero time. The instant of time which is after the origin of time is called positive time and the instant of, which is taken before the origin of time is called negative time.

Question 19. If the displacement time graph of a particle is parallel to the displacement axis (b) the time axis, what will be the velocity particle? Why? Answer: (a) When the displacement-time graph is parallel to the displacement axis, the velocity of the particle is infinity. We know that velocity = \(\frac{\Delta \mathrm{x}}{\Delta \mathrm{t}}\) when the graph is parallel to the displacement axis, then Δt = 0, so velocity = infinity.

(b) When the displacement-time graph is parallel to the time axis, the velocity of the particle is zero as in this case Δx = 0.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 16

Question 21. Define displacement. What are its characteristics? Answer: It is defined as the change in the position of an object in a particular direction.

Characteristics of displacement:

It is a vector quantity.
It has units of length.
The magnitude of displacement is called distance.
The diode valve curve between voltage and current is quite like curve ABCD.

Question 23. What are the important points about the uniform motion? Answer: The following are some important points about the uniform motion:

The velocity in uniform motion does not depend upon the time interval (t 2 – 1,).
The velocity in uniform motion is independent of the choice of origin.
The average and the instantaneous velocities have the same value in uniform motion.
No force acts on the object having uniform motion.
Velocity is taken to be positive when the object moves toward the right of the origin and it is taken -ve if an object moves toward the left of the origin.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 17

In case of zero relative velocity the two vectors \(\vec{A}\) and \(\vec{B}\) will have the same magnitude as shown in fig. (a) and when the relative velocity is non-zero, the length of the two vectors i.e. the magnitude of vectors is different even though they are parallel and is shown in fig.(b).

Question 26. Prove that the distance travelled by an object in nth second is given by Snth = u + \(\frac{a}{2}\) (2n – 1) Answer: Derivation: Let Sn and Sn-1 be the distances covered by an object in n and n-1 seconds respectively. Let u = its initial velocity a = acceleration produced in the object

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 19

Question 27. Is it possible that the velocity of an object be in a direction other than the direction of acceleration? When? Answer: Yes, when a body moves in a circular path, then the direction of the velocity is along the tangent to the point on the circle and the acceleration is always towards its centre.

Question 28. Is the rate of change of acceleration with the time important to describe the motion of a body? Why? Answer: No, because it is observed that only velocity and acceleration are sufficient to understand and explain the motion of a body.

Question 29. Explaining with an example, why does a person sitting in a train think that the other train is at rest when both are moving on parallel tracks with the same speed and in the same direction? Answer: This is because the relative velocity of the train in which the person is sitting w.r.t. the other train is zero. e.g. Let two trains A and B are moving along east with a velocity of 50 km/h i.e. v A = v B = 50 kmh1.

∴ relative velocity of A w.r.t. B is given by V AB = v A – v B = 50 – 50 = 0.

Question 30. Can a body be said to be at rest as well as in motion? Explain. Answer: Yes, both rest and motion are relative terms. A body at rest w.r.t. one object may be in motion w.r.t. another object, e.g. a person sitting in a moving train is at rest w.r.t. other passengers in the train but at the same time, he is in motion w.r.t. the surroundings (trees or buildings) on the side of the track.

Motion in a Straight Line Important Extra Questions Long Answer Type

Question 1. Define the following terms : (a) speed Answer: Speed : It is defined as the time rate of change of position i. e. distance of an object.

i.e. Speed = \(\frac{\text { Distance travelled by the object }}{\text { Time taken }}\)

(b) uniform speed Answer: Uniform Speed: An object is said to be moving with uniform speed if it covers equal distances in equal small intervals of time.

(c) variable speed Answer: Variable Speed: An object is said to be moving with variable speed if it covers equal distances in unequal small intervals of time.

(d) average speed Answer: Average Speed: It is used to measure the variable speed of an object.

It is defined as the ratio of the total distance travelled by the object to the total time taken. ∴ vav = \(\frac{\text { Total }}{\text { Total time taken }}\)

(f) velocity Answer: Velocity: It is defined as the time rate of change of displacement of an object.

(g) uniform velocity Answer: Uniform Velocity: An object is said to be moving with uniform velocity if it undergoes equal displacements in equal intervals of time however small these intervals may be.

(h) variable velocity Answer: Variable Velocity: An object is said to be moving with variable velocity if either its magnitude (i.e. speed) or its direction or both change with time.

(i) uniform motion Answer: Uniform Motion: An object is said to be in uniform motion if it undergoes equal displacements in equal intervals of time which may be very small.

(j) average velocity in uniform Answer: Average Velocity in Uniform Motion: The velocity of an object in uniform motion may be defined as the ratio of the .displacement of the object to the total time interval for which the motion takes place. i.e. v = \(\frac{x_{2}-x_{1}}{t_{2}-t_{1}}\)

(k) relative velocity motion Answer: Relative Velocity: The relative velocity of a moving object with respect to another object is defined as the rate of change of relative position of one object w.r.i. another object. Or It is the velocity with which one object moves with respect to another object.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 22

(m) acceleration Answer: Acceleration: It is defined as the time rate of change of velocity of an object. It is a vector quantity.

(n) retardation Answer: Retardation: It is defined as the negative acceleration produced in the object.

(o) variable acceleration Answer: Variable Acceleration: An object is said to be moving with variable acceleration if its velocity changes by unequal magnitudes in equal intervals of time.

(p) average acceleration Answer: Average Acceleration: It is defined as the ratio of change in velocity in a given time interval to the total time taken.

(q) uniform acceleration Answer: Uniform Acceleration: An object is said to be moving with uniform acceleration if it undergoes equal changes in velocity in equal intervals of time.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 23

2. The position-time graph for a stationary object is a straight line parallel to the time axis. Here the slope of the curve is zero, which means the object is stationary as v = 0.

(iii) s = ut + \(\frac{1}{2}\) at 2 . Answer: Derivation: Let x 1 , V 1 = position and velocity of the object at time t 1 . x 2 , v 2 = position and velocity of the object at time t 2 . a = uniform acceleration of the object.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 32

Numerical Problems:

Question 1. In a car race, car A takes a time t s less than car B and finishes the finishing point with a velocity v more than that of car B. Assuming that the cars start from rest and travel with constant acceleration a, and a respectively show that v = t\(\sqrt{\mathbf{a}_{1} \mathbf{a}_{2}}\) Answer: Let v 1 , v 2 be the finishing velocities of car A and car B respectively. Let t 1 , t 2 be the finishing time-intervals for car A and car B respectively. d = distance travelled by both cars. ∴ according to the statement V = v 1 – v 2 ….(i) t = t 2 – t 1 …(ii)

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 35

If t = total time of journey, then t = t 1 + t 2 … (i)

Also let v = maximum velocity reached (1) For accelerated motion, using equations, v = u + at, we get v = 0 + αt 1 or v = αt 1 … (ii)

(2) For decelerated motion, here, u = v, final velocity is zero. ∴ 0 = v + (- β)t 2 v = βt 2 …(iii)

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 39

Question 3. The driver of a train moving at a speed v 1 sights another train at a distance d ahead of hint moving in the same direction with a slower speed v 2 . He applies brakes and gives a constant deacceleration ‘a’ to his train. Show that there will be no collision if d > \(\frac{\left(\mathbf{v}_{1}-\mathbf{v}_{2}\right)^{2}}{2 \mathbf{a}}\) Answer: Let the collision be just avoided i.e. the rear train comes to rest after travelling a distance d with a declaration ‘a’. the initial speed of 1 st train = v 1 the initial speed of 2nd train = v 2 If u = initial relative speed of 1 st w.r.t. 2nd train, then u = v 1 – v 2

Final velocity of rear train v = 0 ∴ using equations, v 2 – u 2 = 2as, we get 0 – (v 1 – v 2 ) 2 = 2(- a) d (Here a = -a, s = d.) d = \(\frac{\left(\mathbf{v}_{1}-\mathbf{v}_{2}\right)^{2}}{2 \mathbf{a}}\) Thus there will be no collision, if d > \(\frac{\left(\mathbf{v}_{1}-\mathbf{v}_{2}\right)^{2}}{2 \mathbf{a}}\)

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 73

Question 5. A body travels half of its total path in the last second of its fall from rest. Calculate the time and height of fall. Answer: Let h = height of fall t = time of fall a = g = 9.8ms -2 u = 0

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 44

Question 7. When the speed of the car is y, the minimum distance over which it can be stopped is z. If the speed of the car becomes v, then what will be the minimum distance over which it can be stopped? Answer: Case I: Here, the initial velocity of car = v The final velocity of car = 0

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 50

Question 8. A body describes 10m in the third second and 12m in the Sth second with uniform acceleration. Find the distance covered by it in : (a) next 3′ seconds and (b) 8th second of its motion. Answer: Let the initial velocity of body = v and let acceleration of body = a Also, we know that distance covered during the nth second is given by S n th =u + \(\frac{a}{2}\)(2n – 1)

∴ Distance travelled by the body in next 3 seconds is given by = x 2 – x 1 = 92 – 50 = 32 m

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 55

Question 9. The velocity of an object (ms -1 ) moving along a straight line is given by v = 10 + 3t 2 …. (1) Find (a) change in velocity in the interval when t = 2s and 5s. (b) average acceleration in the same interval. (c) instantaneous acceleration at t = 4s. Answer: Comparing equation (1), with the equation v = u + at, we find that u = 10ms -1 , (a) Now velocity of the object after 2 and 5 seconds is calculated as : v = 10 + 3t 2 putting t = 2, v = 10 + 3 × 22 = 10 + 3 × 4 = 22ms -1 putting t = 5, v = 10 + 3 × 52 = 10 + 3 × 25 = 85 ms -1 . ∴ Change in velocity from 2s to 5 s = 85 – 22 = 63 ms -1 .

(b) We know that average acceleration in a given time interval is given by a av = \(\frac{\Delta \mathrm{v}}{\Delta \mathrm{t}}\)

Thus aav in the interval 2s to 5 is given by a av = \(\frac{85-22}{5-2}=\frac{63}{3}\) = 21 ms -2 .

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 56

Question 10. A car travels at a rate of 30 km h -1 for 5 minutes and then at 40 km h -1 for 10 minutes. Find (i) the total distance covered by the car (ii) the average speed of the car. Answer: v 1 = 30 kmh -1 t 1 = 5 min = \(\frac{5}{60}\) h = \(\frac{1}{12}\) h. If S 1 be the distance covered in 5 min., then S 1 = v 1 t 1 = 30 × \(\frac{1}{12}\) = \(\frac{5}{2}\) km = 2.5 km

Now v 2 = 40 kmh -1 , t 2 = 10 minutes = \(\frac{1}{6}\) h

If S 2 = distance covered in 10 min., then S 2 = v 2 t 2 = 40 × \(\frac{1}{6}\) = \(\frac{20}{3}\) km = 6.67 km.

(i) If S be the total distance, then S = S 1 + S 2 = 2.5+ 6.67 = 9.17 km.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 57

Question 11. A particle covered half the distance with a velocity v0. The remaining half distance was covered with a velocity v 1 for half the time and with velocity v 2 for another half of the time. Find the mean speed of the particle averaged over the whole time of motion. Answer: Let S = total distance covered by the particle. t 1 = time taken to cover half the distance i.e. \(\frac{S}{2}\)

v 0 = velocity of the particle \(\frac{S}{2}\) = Distance covered with v 0 .

Question 12. In a circus, a motorcyclist takes 4 rounds on the same track in the globe of radius r with a velocity 5r. Find (i) total displacement Answer: radius of track = r, velocity v = 5r. As the starting and endpoint in a circular track are the same, so the net displacement = 0

(ii) total distance covered Answer: Distance covered in one round = perimeter of the circular track of radius r = 2π x r ∴ total distance covered in 4 rounds = 4 × 2πr = 8πr.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 61

Question 13. The displacement of a particle moving in one dimension under the action of a constant force is related to the time t by the equation t = \(\sqrt{x}\) + 3, where x is in metre and t is in second. Find the displacement of the particle when its velocity is zero. Answer: t = \(\sqrt{x}\) + 3

\(\sqrt{x}\) = t – 3 ….(1)

Squaring on both sides of equation (1), we get x = (t – 3) 2 = t 2 + 9 – 6t …..(2)

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 62

Question 14. A car moving along a straight road with a speed of 144 km h -1 is brought to a stop within a distance of 200 m. Calculate its retardation and the time it takes to stop. Answer: Here, S = distance covered before topping = 200 m. u = initial speed of car = 144 km h -1 = 144 × \(\frac{5}{18}\) ms -1 = 40 ms -1 v = its final speed = 0

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 64

Question 15. A stone falls from the top of the tower in 8s. How much time will it take to cover the first quarter of the distance starting from the top? Answer: Here u = initial speed oftcie = 0 h = height of tower t = time taken in falling by h = 8s

Let t 1 = time taken to cover first quarter i.e. \(\frac{h}{4}\) = ? a = g = acce. due to gravity

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 66

Question 16. A ball is thrown vertically upwards with a velocity of 30 ms -1 . If access. due to gravity is 10 ms -2 , what will be the distance travelled by ¡tin the first and last second of upward motion? Answer: Here, u = initial velocity in the upward direction 30ms -1 Let after a time t, the ball stops i.e. v = 0 a = acce.= g = 10 ms -2

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 67

Question 17. A rocket is fired vertically from the ground. It moves upwards with a constant acceleration of 10 ms -2 for the 30s after which the fuel is consumed. After what time from the instant of firing, the rocket will attain the maximum height? Take g = 10ms -2 . Answer: Here, a = g = 10ms -2 for t = 30s ∴ u = 0 for first part of the motion v = velocity attained by the rocket after 30s = ?

∴ using the relation, v = u + at …(1) we get v = 0 + 10 × 30 = 300 ms -1

for second part of motion, u = v = 300 ms -1 v 1 = final velocity = 0

Let t1 be the time of journey for this part of the motion, ∴ from equation (1), we get 0 = 300 – 10 × t 1

Let T = total time of flight in which the rocket attains maximum height, T = t + t 1 = 30 + 30 = 60 second.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 70

If S be the total distance covered by two cars before coming to rest, then S = S 1 + S 2 = 40 + 27.7 = 67.7 m.

Also S 1 = 80 m. Now clearly the total distance covered by the cars before coming to rest is less than 80 m, so the collision will be averted.

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 72

Question 22. A car starting from rest and moving with uniform acceleration possesses average velocities 5 ms -1 , 10 ms -1 and 15 ms -1 in the first, second and third seconds. What is the total r distance covered by the car in these three seconds? Answer: Here, let v 1 , v 2 and v 3 be the average velocities of 1st, 2nd and 3rd secs, respectively. ∴ v 1 = 5 ms -1 , v 2 = 10 ms -1 , v 3 = 15 ms -1 t 1 = t 2 = t 3 = 1 s = time intervals

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 81

Let C be their meeting point after a time t. If BC = x, then usirig the relation, S = ut + \(\frac{1}{2}\) at2, we get

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 83

Question 24. The displacement of a body along the x-axis changes according to the relation: x = 20 – 15t + 4t 2 , where x is in metres, t in seconds. Determine its position, velocity and acceleration at t = O. Answer: Here, x = 4t 2 – 1 5t + 20 … (1) v = \(\frac{\mathrm{d} \mathrm{x}}{\mathrm{dt}}\) = 4.2t – 15 = 8t – 15 …(2)

Also a = \(\frac{\mathrm{d} \mathrm{v}}{\mathrm{dt}}\) = 8 At t = 0, the position (x), velocity (y) and acceleration (a) are given by x = 4.0 – 15 × 0 + 20 = 20 m v = 8 × 0 – 15 = – 15ms -1 and a = 8 ms -2 .

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 84

Value-Based Type:

Question 1. On a two-lane road, there are hoardings hanged on the electric poles “Save Energy”. If car a is travelling at a speed of 54 km h1 and car ‘B’ moves with 90 km h -1 from the opposite direction. Now, answer these questions: (a) Which values are depicted in the above problem? Write down the four ways by which the energy can be saved. Answer: Save energy to save our environment.

The four ways to save energy are as under :

By using CFLs, switching off appliances when not in use.
Saving water by using it efficiently.
Using solar energy.
By using public transport.

(b) Write a slogan on “save energy”. Answer: Try your self

(c) Find the velocity of B with respect to A? Also, find the velocity of the ground with respect to B? Solution: V A = + 54 km h -1 = 15 ms -1 V B = 90 km h -1 = – 25 ms -1

(Takingthe velocity of car A positive N v and car B negative) ∴ Relative velocity of B with respect to A = V B – V A = – 25 – 15 = – 40 ms -1

i.e the car Bappers to A to move with a speed 40 ms-1 from opposite direction. Relative velocity of ground w.r.t B = 0 – V B = 0 – (- 25) = 25 ms -1

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 86

(ii) Find the (a) Displacement Answer: Displacement = minimum distance between initial and final point = AB = 2 R

Question 3. In sports day activities of a public school, the lines were drawn with chalk powder. Gagandcep an athlete runs a distance of 1500 m in the following manner, (i) Starting from rest, he accelerates himself uniformly at 2ms_1, till he covers a distance of 900 m. (ii) He then runs the remaining distance of 600 m at the uniform speed developed. (i) Which value is depicted in the above problem? Answer: Importance of sports activities.

Question 4. An old woman crossing the road was holding a money purse. She was not able to walk. A pickpocket snatches away her purse. A school student of class XI having seen this incident tries to help that old lady. He informs the polic^inspector who stands nearby. The inspector collects the money purse from the pickpocket and hands it over to the old lady. (a) What value do you find in the school student? Answer: The student is sympathetic towards others, helping, and applies his presence of mind in solving the problems, knows how to use public services.

(b) Also the police inspector in a jeep is chasing the pickpocket on a straight road. The jeep is going at its maximum speed ‘v’. The pickpocket rides on the motorcycle of a waiting friend when the jeep is at a distance ‘d’ away. And the motorcycle starts with a constant acceleration ‘a’. Show that the pickpocket will be caught if v ≥ \(\sqrt{2ad}\). Answer: Let the police inspector catches the pickpocket after time t. The distance covered by the pickpocket in this time interval is given by: s = \(\frac{1}{2}\) at 2

Class 11 Physics Important Questions Chapter 3 Motion in a Straight Line 93

The police inspector will catch the bus if t is real i.e v 2 ≥ 2ad or v ≥ \(\sqrt{2ad}\) Hence, the minimum speed of the police inspector for catching the pickpocket is \(\sqrt{2ad}\) proved.

NCERT Solutions for Class 6, 7, 8, 9, 10, 11 and 12

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line are part of Class 11 Physics NCERT Solutions . Here we have given NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line.

Topics and Subtopics in NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line :


3	Motion in a Straight Line
3.1	Introduction
3.2	Position, path length and displacement
3.3	Average velocity and average speed
3.4	Instantaneous velocity and speed
3.5	Acceleration
3.6	Kinematic equations for uniformly accelerated motion
3.7	Relative velocity

NCERT Solutions Class 11 Physics Physics Sample Papers

QUESTIONS FROM TEXTBOOK

Question 3. 1. In which of the following examples of motion, can the body be considered approximately a point object. (a) A railway carriage moving without jerks between two stations. (b) A monkey sitting on top of a man cycling smoothly on a circular track. (c) A spinning cricket ball that turns sharply on hitting the ground. (d) A tumbling beaker that has slipped off the edge of table. Answer: (a) The railway carriage moving without jerks between two stations, so the distance between two stations is considered to be large as compared to the size of the train. Therefore the train is considered as a point object. (b) The monkey may be considered as point object because value of distance covered on a circular track is much greater. (c) As turning of ball is not smooth, thus the distance covered by ball is not large in the reasonable time. Therefore ball cannot be considered as point object. (d) Again a tumbling beaker slipped off the edge of a table cannot be considered as a point object because distance covered is not much larger.

More Resources for CBSE Class 11

NCERT Solutions

NCERT Solutions Class 11 Maths
NCERT Solutions Class 11 Physics
NCERT Solutions Class 11 Chemistry
NCERT Solutions Class 11 Biology
NCERT Solutions Class 11 Hindi
NCERT Solutions Class 11 English
NCERT Solutions Class 11 Business Studies
NCERT Solutions Class 11 Accountancy
NCERT Solutions Class 11 Psychology
NCERT Solutions Class 11 Entrepreneurship
NCERT Solutions Class 11 Indian Economic Development
NCERT Solutions Class 11 Computer Science

Question 3. 5. A jet airplane travelling at the speed of 500 km h-1 ejects its products of combustion at the speed of 1500 km h -1 relative to the jet plane. What is the speed of the latter with respect to an observer on the ground? Answer: Velocity of jet airplane w.r.t observer on ground = 500 km/h. If Vj and v0 represent the velocities of jet and observer respectively, then vj – vo = 500 km h -1 Similarly, if vc represents the velocity of the combustion products w.r.t jet plane, then vc – vg = -1500 km/h The negative sign indicates that the combustion products move in a direction opposite to that of jet. Speed of combustion products w.r.t. observer = vc – u0 = (vc – vj) + (vj – v0) = (-1500 + 500) km h -1 = -1000 km h -1 .

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line Q6

Question 3. 11. Read each statement below carefully and state with reasons and examples, if it is true or false; A particle in one-dimensional motion (a) with zero speed at an instant may have non-zero acceleration at that instant. (b) with, zero speed may have non-zero velocity. (c) with constant speed must have zero acceleration, (d) with positive value of acceleration must be speeding up. Answer: (a) True. Consider a ball thrown up. At the highest point, speed is zero but the acceleration is non-zero. (b) False. If a particle has non-zero velocity, it must have speed. (c) True. If the particle rebounds instantly with the same speed, it implies infinite acceleration which is physically impossible. (d) False. True only when the chosen position direction is along the direction of motion.

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line Q12

Question 3. 13. Explain clearly, with examples, the distinction between: (a) Magnitude of displacement (sometimes called distance) over an interval of time, and the total length of path covered by a particle over the same interval; (b) Magnitude of average velocity over an interval of time, and the average speed over the same interval. (Average speed of a particle over an interval of time is defined as the total path length divided by the time interval). Show in both (a) and (b) that the second quantity is either greater than or equal to the first. When is the equality sign true? [For simplicity, consider one dimensional motion only], Answer: (a) Suppose a particle goes from point A to B along a straight path and returns to A along the same path. The magnitude of the displacement of the particle is zero, because the particle has returned to its initial position. The total length of path covered by the particle is AB + BA = AB + AB = 2 AB. Thus, the second quantity is greater than the first, (b) Suppose, in the above example, the particle takes time t to cover the whole journey. Then, the magnitude of the average velocity of the particle over time-interval t is = Magnitude of displacement /Time-interval =0/t =0 While the average speed of the particle over the same time-interval is =Total path length /Time-interval= 2 AB /t Again, the second quantity (average speed) is greater than the first (magnitude of average velocity). Note: In both the above cases, the two quantities are equal if the particle moves from one point to another along a straight path in the same direction only.

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line Q14

Question 3. 15. In Exercises 3.13 and 3.14, we have carefully distinguished between average speed and magnitude of average velocity. No such distinction is necessary when we consider instantaneous speed and magnitude of velocity. The instantaneous speed is always equal to the magnitude of instantaneous velocity. Why? Answer: Instantaneous velocity is the velocity of a particle at a particular instant of time. In this case of small interval of time, the magnitude of the displacement is effectively equal to the distance travelled by the particle in the same interval of time. Therefore, there is no distinction between instantaneous velocity and speed.

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line Q16

NCERT Solutions for Class 11 Physics All Chapters

Chapter 1 Physical World
Chapter 2 Units and Measurements
Chapter 3 Motion in a Straight Line
Chapter 4 Motion in a plane
Chapter 5 Laws of motion
Chapter 6 Work Energy and power
Chapter 7 System of particles and Rotational Motion
Chapter 8 Gravitation
Chapter 9 Mechanical Properties Of Solids
Chapter 10 Mechanical Properties Of Fluids
Chapter 11 Thermal Properties of matter
Chapter 12 Thermodynamics
Chapter 13 Kinetic Theory
Chapter 14 Oscillations
Chapter 15 Waves

We hope the NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line help you. If you have any query regarding NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line, drop a comment below and we will get back to you at the earliest.

Free Resources

Quick Resources

New QB365-SLMS
12th Standard Materials
11th Standard Materials
10th Standard Materials
9th Standard Materials
8th Standard Materials
7th Standard Materials
6th Standard Materials
12th Standard CBSE Materials
11th Standard CBSE Materials
10th Standard CBSE Materials
9th Standard CBSE Materials
8th Standard CBSE Materials
7th Standard CBSE Materials
6th Standard CBSE Materials
Tamilnadu Stateboard
Scholarship Exams
Scholarships

CBSE 11th Physics Motion in a Straight Line Chapter Case Study Questions with Answers

By QB365 on 22 Jan, 2024

Motion in a Straight Line

11th Physics CBSE case study questions for Motion in a Straight Line - 2024

CBSE 11th Physics Motion in a Straight Line Chapter Case Study Question with Answers

CBSE Class 11th Physics Sample Model Question Papers. CBSE Class 11th Physics Sample Case Study Questions with Answer Keys. CBSE 11th Physics Model Question Papers Case Study Questions CBSE 11th Physics CBSE Case Study Question and Answers CBSE 11th Physics CBSE Question Papers with Answer Keys Motion in a Straight Line Model Question Paper 11th Physics with Answer Keys Motion in a Straight Line 11th CBSE Physics Question Papers with Answer Keys. Model Question Paper for 11th Physics CBSE CBSE Model Question Papers Class 11th 2024 Model Question Paper 11th Physics

Related 11th Standard CBSE Physics Materials

11th standard cbse syllabus & materials, cbse 11th chemistry structure of atom chapter case study question with answers, cbse 11th chemistry some basic concept of chemistry chapter case study questions with answers, 11th biology biological classification chapter case study question with answers cbse, 11th biology the living world chapter case study question with answers cbse, class 11th business studies - internal trade case study questions and answers 2022 - 2023, class 11th business studies - social responsibilities of business and business ethics case study questions and answers 2022 - 2023, class 11th business studies - emerging modes of business case study questions and answers 2022 - 2023, class 11th business studies - business service case study questions and answers 2022 - 2023, class 11th business studies - private, public and global enterprises case study questions and answers 2022 - 2023, class 11th business studies - business, trade and commerce case study questions and answers 2022 - 2023.

Class 11th Applied Mathematics - Coordinate Geometry Case Study Questions and Answers 2022 - 2023

Class 11th applied mathematics - basics of financial mathematics case study questions and answers 2022 - 2023, class 11th applied mathematics - descriptive statistics case study questions and answers 2022 - 2023, class 11th applied mathematics - probability case study questions and answers 2022 - 2023, class 11th applied mathematics - calculus case study questions and answers 2022 - 2023.

Class VI to XII

Tn state board / cbse, 3000+ q&a's per subject, score high marks.

11th Standard CBSE Study Materials

11th Standard CBSE Subjects

Motion In A straight Line, Distance And Displacement, Important Topics For JEE 2024

Motion In A straight Line : Motion in a straight line is called straight motion. If the direction of a moving object is constant and the object is moving at a constant speed, then it is moving in a straight line. In this case, the object is said to be moving in a straight line at constant speed.

February 24, 2024

Table of Contents

Motion In A straight Line : When hearing the names of physical quantities distance and displacement, we may think that they both are the same. But they are different actually. Distance is the measure of the total path length covered and displacement is the measure of how much an object got displaced.

Rest, motion And Position In JEE Physics Syllabus

We can see a lot of objects around us. We can say that either those objects are at rest or in motion. If an object does not change its position with respect to time, we can say that the object is at rest. If the object changes its position with respect to time, the object is said to be in motion. Stating whether an object is at rest or in motion is meaningless without an observer.

Best Books For JEE Main 2024 : Click to Check

That means, there is no such thing as absolute rest or in absolute motion. The position of an object can be described using the frame of reference. Convenient and the most accepted way of choosing a frame of reference is three mutually perpendicular axes named X-Y-Z. The position of the object with respect to this frame of reference is specified by the x , y and z coordinates.

How Many Marks Required To Score 90 Percentile In JEE Main 2024 : Click to Check

Distance In JEE Physics Syllabus

When you are coming back from school, you will have to travel on the road. In the figure, you can see that the student has to travel on six straight roads. By measuring the lengths of each road and adding them up, we will get the total distance travelled.

Thus, distance is the total path length covered from the initial position to the final position. Distance is a scalar quantity. The SI unit of distance is metre ( m ).

JEE Main Exam Pattern 2024 : Click to Check

Displacement In JEE Physics Syllabus

Even though you have to travel on different roads to reach home from school, we can draw a straight line connecting the school and home. If we construct a road through this straight line, we know that it will be the shortest distance from school and home, unfortunately, we can’t do it everywhere. This shortest distance will give us the measure of displacement. So, change in position of an object is called displacement.

Displacement = ∆ x = x f – x 0

x f = Final Position

x 0 = Initial; Position

∆ x = Displacement

In the above figure, we can find the displacement using Pythagoras theorem.

When we mention the displacement of an object, we need to mention the direction in which it was displaced. For example, in this figure, if we consider the school as the origin, the home will be towards the North-East direction.

How To Prepare JEE Main In 2 Month : Click to Check

Thus, displacement requires both magnitude and direction to define it. Therefore, displacement is a vector quantity while distance is a scalar quantity. When a person completes one lap on a circular track of radius r, the distance covered will be equal to the perimeter of the circle. i.e., 2π r . But there’s no change in position for the person. Thus, the displacement of the person is zero. The SI unit of displacement is metre ( m ).

Difference Between Distance And Displacement :


It is the total path length covered	It is the shortest length between final and initial positions.
It is a scalar quantity	It is a vector quantity
It can never have negative values	It can have positive, negative, or even zero values
It can never have a value lesser than displacement.	It can have a value either equal to or less than distance.

JEE Main Result 2024 : Click to Check

Distance And Displacement Examples

1. A person moves on a semicircular track of radius 40 m . If he starts at one end of the track and reaches the other end, find the magnitude of displacement of the person.

Answer: Displacement = Diameter = 2 × Radius = 2 × 40 m = 80 m .

JEE Main Marks Vs Percentile : Click to Check

2) A car moves from O to D along the path OABCD shown in figure. What is distance travelled and net displacement.

Distance = 8 km + 4 km + 4 km + 1 km = 17 km .

JEE Main Syllabus 2024 : Click to Check

Motion In A straight Line FAQs

Ans : Distance is the measure of the total path length covered.

Ans. Displacement is the measure of how much an object got displaced. That is the shortest length between final and initial positions.

Ans. Yes, displacement can have both positive, negative, and zero values depending on the direction of motion. But distance can have only positive values.

Ans. Yes. If an object covers a distance and reaches back to the initial position, the object possesses a non-zero value for distance. But, when calculating the displacement, both initial and final positions are the same. So, the change in position is zero. Thus, we got zero displacement for an object with non-zero distance covered.

Ans- We know that distance is the magnitude of the path length covered and independent of the direction of motion. Hence, distance is a scalar quantity. On the other side,

Death Well Or Rotor, Centrifugal Force, Important Topics For JEE Main Physics 2024

Gravitational Potential, Important Topics For JEE Main Physics 2024

.st1{display:none} Related Articles

What Are The Scoring Topics In JEE Advanced 2025, Subject Wise Weightage And Topics
Top 10 Best Revision Techniques for JEE 2025 Exam, Self Revision Test, Study Notes
Toppers Strategy For JEE Main 2025, Time Management, Important Topics
What Is Percentile In JEE? JEE Main Percentile Calculator, Important Points
NIT Patna B.Tech Admission 2024, Cutoff, Seat Matrix, Course Details, Important Updates
JEE Advanced Syllabus 2025, Check Subject-Wise Important Topics
JEE Main 2025 Calculus Weightage, Important Topics For JEE Mathematics
Is JEE Advanced Tough For 2025?, Important Preparation Tips, Strategy, Exam Dates
Most Important Chapters for JEE Main 2025, Check Subject Wise Key Topics to Ace JEE 2025
JEE Main Syllabus 2025, Check Subject-Wise Detailed Syllabus, Important Topics

Have doubts?

Our support team will be happy to assist you!

Andhra Pradesh
Chhattisgarh
West Bengal
Madhya Pradesh
Maharashtra
Jammu & Kashmir
NCERT Books 2022-23
NCERT Solutions
NCERT Notes
NCERT Exemplar Books
NCERT Exemplar Solution
States UT Book
School Kits & Lab Manual
NCERT Books 2021-22
NCERT Books 2020-21
NCERT Book 2019-2020
NCERT Book 2015-2016
RD Sharma Solution
TS Grewal Solution
TR Jain Solution
Selina Solution
Frank Solution
Lakhmir Singh and Manjit Kaur Solution
I.E.Irodov solutions
ICSE - Goyal Brothers Park
ICSE - Dorothy M. Noronhe
Micheal Vaz Solution
S.S. Krotov Solution
Evergreen Science
KC Sinha Solution
ICSE - ISC Jayanti Sengupta, Oxford
ICSE Focus on History
ICSE GeoGraphy Voyage
ICSE Hindi Solution
ICSE Treasure Trove Solution
Thomas & Finney Solution
SL Loney Solution
SB Mathur Solution
P Bahadur Solution
Narendra Awasthi Solution
MS Chauhan Solution
LA Sena Solution
Integral Calculus Amit Agarwal Solution
IA Maron Solution
Hall & Knight Solution
Errorless Solution
Pradeep's KL Gogia Solution
OP Tandon Solutions
Sample Papers
Previous Year Question Paper
Important Question
Value Based Questions
CBSE Syllabus
CBSE MCQs PDF
Assertion & Reason
New Revision Notes
Revision Notes
Question Bank
Marks Wise Question
Toppers Answer Sheets
Exam Paper Aalysis
Concept Map
CBSE Text Book
Additional Practice Questions
Vocational Book
CBSE - Concept
KVS NCERT CBSE Worksheets
Formula Class Wise
Formula Chapter Wise
Toppers Notes
Most Repeated Question
Diagram Based Question
Study Planner
JEE Previous Year Paper
JEE Mock Test
JEE Crash Course
JEE Sample Papers
Important Info
SRM-JEEE Previous Year Paper
SRM-JEEE Mock Test
VITEEE Previous Year Paper
VITEEE Mock Test
BITSAT Previous Year Paper
BITSAT Mock Test
Manipal Previous Year Paper
Manipal Engineering Mock Test
AP EAMCET Previous Year Paper
AP EAMCET Mock Test
COMEDK Previous Year Paper
COMEDK Mock Test
GUJCET Previous Year Paper
GUJCET Mock Test
KCET Previous Year Paper
KCET Mock Test
KEAM Previous Year Paper
KEAM Mock Test
MHT CET Previous Year Paper
MHT CET Mock Test
TS EAMCET Previous Year Paper
TS EAMCET Mock Test
WBJEE Previous Year Paper
WBJEE Mock Test
AMU Previous Year Paper
AMU Mock Test
CUSAT Previous Year Paper
CUSAT Mock Test
AEEE Previous Year Paper
AEEE Mock Test
UPSEE Previous Year Paper
UPSEE Mock Test
CGPET Previous Year Paper
BCECE Previous Year Paper
JCECE Previous Year Paper
Crash Course
Previous Year Paper
NCERT Based Short Notes
NCERT Based Tests
NEET Sample Paper
Previous Year Papers
Quantitative Aptitude
Numerical Aptitude Data Interpretation
General Knowledge
Mathematics
Agriculture
Accountancy
Business Studies
Political science
Enviromental Studies
Mass Media Communication
Teaching Aptitude
Verbal Ability & Reading Comprehension
Logical Reasoning & Data Interpretation
CAT Mock Test
CAT Important Question
CAT Vocabulary
CAT English Grammar
MBA General Knowledge
CAT Mind Map
CAT Study Planner
CMAT Mock Test
SRCC GBO Mock Test
SRCC GBO PYQs
XAT Mock Test
SNAP Mock Test
IIFT Mock Test
MAT Mock Test
CUET PG Mock Test
CUET PG PYQs
MAH CET Mock Test
MAH CET PYQs
NAVODAYA VIDYALAYA
SAINIK SCHOOL (AISSEE)
Mechanical Engineering
Electrical Engineering
Electronics & Communication Engineering
Civil Engineering
Computer Science Engineering
CBSE Board News
Scholarship Olympiad
School Admissions
Entrance Exams
All Board Updates
Miscellaneous
State Wise Books
Engineering Exam

Motion In A Straight Line Notes for JEE Physics

Free pdf download.

SHARING IS CARING If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Candidates preparing for the JEE entrance exam, need to have proper study material. Through the study material, students can easily score good marks in the chapter Motion In A Straight Line. Study material includes Motion In A Straight Line Notes for JEE and some practice problems with answers. Both notes and practice problems for the chapter Motion In A Straight Line can be downloaded from anywhere. JEE aspirants can easily download Motion In A Straight Line Notes for JEE through any of the electronic devices: laptop, mobile phone, etc.

Through the Motion In A Straight Line Notes, JEE students studying in class 11 can also be benefited from it. As the chapter Motion In A Straight Line are also included in the class 11th syllabus. Students can practise problems with answers included in the chapter 5 Motion In A Straight Line.

Motion In A Straight Line Notes for JEE PDF

Selfstudys provides the chapter’s notes related to the chapter Motion In A Straight Line are given in the PDF form. Through the Motion In A Straight Line Notes for JEE PDF, students can easily download it from anywhere. With the help of notes, students can understand every topic in a comprehensive way. In some advanced level questions, students need to answer in a comprehensive way so that they can score well. Through these notes, students can give answers in a comprehensive and in an elaborate way.

Practise Problems with Answers for Motion In A Straight Line

After completing the theory part of the chapter Motion In A Straight Line, students need to practise questions from the PDF. Candidates need to practise these questions so that they can have deep knowledge of the chapter. After solving the questions, candidates can refer to the solutions if there is any doubt. Through these questions provided in the Portable Document Format (PDF), students can easily improvise their marks. According to these marks, candidates would be able to easily select their desired college. However, scoring good marks in one subject is not enough to get a desired college; overall score matters.

How to Download the Motion In A Straight Line Notes for JEE?

Students should have easy access to the notes and some questions for the chapter Motion In A Straight Line. Steps to download the PDF are-

Open Selfstudys website.

Motion In A Straight Line Notes, Motion In A Straight Line Notes for Physics, Motion In A Straight Line Notes PDF for JEE, JEE Notes for Motion In A Straight Line, Download Motion In A Straight Line Notes, How to Download the Motion In A Straight Line Notes for JEE

A new page will appear, select notes from the list.
Select the chapter Motion In A Straight Line, again a new page will appear.

Now students can easily go through the theory and some questions to practise.

Features of Motion In A Straight Line Notes for JEE

Class notes are very crucial throughout the JEE entrance examination. As without the notes, students would not be able to cover the topics. Some of the important features of the Motion In A Straight Line Notes for JEE are:

PDF- The PDF is divided into two parts : theory and questions related to the chapter.These notes are arranged in a systematic manner so that students search for it without any difficulty. Questions in this PDF are asked according to the concepts explained inside the chapter.
Index- Contents included in the chapter are briefly given. With this brief, students can easily get an idea about the topics that need to be covered in the chapter. The brief about the content can be helpful for both teachers and students. According to this brief, students and teachers can cover the syllabus before the JEE entrance exam.
Elaboration- Every topic and definitions are elaborately discussed in the chapter. Through this explanation students can easily score good marks in the chapter Motion In A Straight Line.
Problems and Answers- Apart from Motion In A Straight Line Notes for JEE, Questions for each topic are also given in the PDF, so that students don’t face any difficulty in understanding the chapter. Solutions can be referred to whenever candidates are in doubt in any of the concepts.
Types of questions- Questions included in the PDF can be both basic and advanced level of questions. By practising Motion In A Straight Line questions students can score well in advance level questions.

Advantages of Motion In A Straight Line Notes for JEE

Students can be benefited with the help of Motion In A Straight Line Notes for JEE as this is a very important study tool. Some important advantages of the notes are:

Focus Throughout the Preparation: Through Motion In A Straight Line Notes for JEE, students can easily focus on the studies throughout the JEE entrance exam.
Comprehensive Skill: By studying through the notes, students can increase their comprehensive skill. Through these skills, students can score good marks in class 11 as well as the JEE entrance examination.
Memorising all the topics: Through these notes, students can increase their ability to memorise the chapter Motion In A Straight Line. As in this chapter students need to remember each and every detail of the chapter.
Accuracy: Through solving questions from the PDF of JEE Physics Motion In A Straight Line Notes, students can improve their accuracy.
Systematic Manner: These notes are provided in an organised and systematic manner. Through the organised form, students can have a clear and concise amount of knowledge.

Tips for Students Preparing for JEE Entrance Exam

All candidates preparing for the JEE entrance exam, need to follow their own path so that students can score well in the entrance exam. According to these marks, candidates can select their desired field. Those preparation tips are:

JEE Physics Syllabus: First step is to go through the JEE Main Syllabus 2023, to identify important topics that need to be covered. For example, Motion In A Straight Line is an important topic that needs to be covered.
Coverage: Complete all the topics and concepts included in the chapter Motion In A Straight Line. This step can be easily covered through Motion In A Straight Line Notes for JEE.
Plenty of Questions: Try to solve practice problems from the portable document format. Through these questions, students can have deep knowledge of all topics included in the chapter. Solve as many questions possible from the PYQs, mock tests, etc.
Solving Doubts: Try to solve the doubts before the JEE entrance exam so that there is no last minute rush. Solving doubts can help students to be focused throughout the entrance exam preparation.
Positive Attitude: Try to maintain a positive attitude throughout the preparation so that one can maintain the confidence level.
Healthy Diet: Try to maintain a healthy diet throughout the preparation so that one’s preparation doesn’t fall behind because of one’s health.
Remain Focused: Throughout the JEE entrance exam preparation, students need to be focused. Remaining focused throughout the preparation can help students to cover all the concepts and topics included in the chapter.

Why is it important for JEE aspirants to refer to Motion In A Straight Line Notes for JEE?

It is very important for JEE aspirants to refer to Motion In A Straight Line notes for JEE because it helps them to be prepared for this particular chapter in many ways. With the help of JEE Notes of Motion In A Straight Line, candidates can understand all the concepts included in the chapter.

Selfstudys website also provides the practice problems for the chapter Motion In A Straight Line in the available Motion In A Straight Line notes PDF. Students can also refer to the answers through the PDF provided in the website. Students can solve the doubts by going through the solutions for these practice problems. By revising the chapter using Motion In A Straight Line notes for JEE aspirants will be able to answer a variety of questions with ease.

LPU University Admissions 2023 upto 100% Scholarship (All Pages)

NCERT Solutions for Class 12 Maths
NCERT Solutions for Class 10 Maths
CBSE Syllabus 2023-24
Social Media Channels
Login Customize Your Notification Preferences

Second click on the toggle icon

Provide prime members with unlimited access to all study materials in PDF format.

Allow prime members to attempt MCQ tests multiple times to enhance their learning and understanding.

Provide prime users with access to exclusive PDF study materials that are not available to regular users.

IMAGES

Motion in a Straight Line Class 11 Physics
Motion in a Straight Line Class 11 Physics
Motion In A Straight Line
SOLUTION: Motion in a straight line class 11-Physics
NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line
Motion In A Straight Line Mind Map

VIDEO

2025 මාපාංක ප්‍රස්ථාර Day 01(2024/03/22)
2026 Advanced Level
2026 Online Class Day 17 ( ත්‍රිකෝණමිතිය Day 06) Chathura & Mayuri
2024 Paper Class Day 01 Part 01 2024/02/11
2026 Advanced Level
2026 Online Class Day 08 (Vectors|දෛශික Day 03) Chathura & Mayuri

COMMENTS

Case Study Questions Class 11 Physics Motion in a Straight Line
CBSE Case Study Questions Class 11 Physics Motion in a Straight Line Case Study - 1. If an object moving along the straight line covers equal distances in equal intervals of time, it is said to be in uniform motion along a straight line. Distance and displacement are two quantities that seem to mean the same but are different with different ...
Case Study Questions for Class 11 Physics Chapter 3 Motion in a
Case Study Questions: Question 1: Average Speed and Average VelocityWhen an object is in motion, its position changes with time. So, the quantity that describes how fast is the position changing w.r.t. time and in what direction is given by average velocity. It is defined as the change in position or displacement (Δx ) divided … Continue reading Case Study Questions for Class 11 Physics ...
Motion in a Straight Line Case Study Questions With Answers
Here, we have provided case-based/passage-based questions for Class 11 Physics Chapter 3 Motion in a Straight Line. Case Study/Passage-Based Questions. Case Study 1: When an object is in motion, its position changes with time. But how fast is the position changing with time and in what direction? To describe this, we define the quantity average ...
11th Physics Motion in a Straight Line Case Study Questions & Answers
Case Study. (i) When a body is moving in straight line in a specific direction then both displacement and distance would be equal in magnitude. (ii) Average speed is the average distance travelled per unit time. \ (\text { or } v=\frac {\text { total distance travelled }} {\text { total time taken }}\) Average velocity is the average ...
Case Based CH-3 Motion in Straight Line
Case Based CH-3 Motion in Straight Line - Free download as PDF File (.pdf), Text File (.txt) or read online for free. The document contains 4 case study based questions with multiple choice sub-questions. Question 1 deals with free fall motion and equations involving displacement, velocity and time. Question 2 involves position, displacement and path length of an object moving along the x-axis.
PDF Kendriya Vidyalaya Sanghathan Chandigarh Region Class-xi Subject ...
5 Case Study Based Questions 22—25 6 Answers Keys of MCQs 26-29 . 3 GIST 1.Motion: ... Ex. motion of a block in a straight line, motion of a train along a straight track, a man walking on a level and narrow road and object falling under gravity etc. 2. Two-Dimensional Motion:(Motion in a Plane)
Chapter 3
CHAPTER 3- MOTION IN A STRAIGHT LINE- CASE STUDY - Free download as PDF File (.pdf), Text File (.txt) or read online for free.
Class 11th Physics
QB365 provides a detailed and simple solution for every Possible Case Study Questions in Class 11 Physics Subject - Motion in a Straight Line, CBSE. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
CBSE Class 11 Physics Chapter 3 Motion in a Straight Line Study Materials
Motion in a Straight Line Class 11 Notes Physics Chapter 3. • Introduction. Motion is one of the significant topics in physics. Everything in the universe moves. It might only be a small amount of movement and very-very slow, but movement does happen. Even if you appear to be standing still, the Earth is moving around the sun, and the sun is ...
Motion in a Straight Line Questions
v=u+gt. = t = (v−u)/g = 2.02 sec. 7) Define uniform motion in a straight line. If a body travels an equal amount of distance in an equal gap or interval of time in a straight line, then it is said to have uniform motion. In simple words, if the rate of change of the velocity of a body remains constant, then the body is said to have uniform ...
Motion in a Straight Line
a= (v−v₀) / t. Then resolve for v as a function of t. v = v₀ + at. The second equation of Motion is written like a polynomial - a constant term (s0), followed by a first-order term (v0t) and followed by a second-order term (½at2). Since the maximum order is 2, it's more accurate to call it a quadratic. ∆s = v₀t + ½at².
PHYS101 Study Guide: Unit 2: Motion in a Straight Line
Unit 2: Motion in a Straight Line. 2a. Compare and contrast distance and displacement. Define distance. Define displacement. Give an example of motion when the distance and displacement are the same. Give an example of motion when the distance and displacement are different. Distance describes how much an object has moved.
NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line
Chapter 3 of NCERT Class 11 Physics textbook, titled "Motion in a Straight Line," discusses the motion of an object in a straight line and its various aspects. The chapter starts by defining the terms related to motion, such as displacement, distance, speed, velocity, and acceleration. The chapter then explains the different types of motion ...
Conceptual Questions Based on Class 11 Physics Motion in A Straight Line
Solution. Not necessarily. If velocity increases, acceleration acts in the direction of velocity and if velocity decreases, then acceleration acts in the opposite direction of velocity. Q.21. A car travelling with a velocity of 50 km/hr on a straight road is ahead of a motor-cycle travelling with a speed of 75 km/hr.
CBSE Case Study Questions Class 11 Physics PDF Download
Chapter-wise Solved Case Study Questions for Class 11 Physics. Chapter 1: Physical World. Chapter 2: Units and Measurements. Chapter 3: Motion in a Straight Line. Chapter 4: Motion in a Plane. Chapter 5: Laws of Motion. Chapter 6: Work, Energy, and Power. Chapter 7: System of Particles and Rotational Motion.
Case Based Questions Test: Motion in a Straight Line
The Case Based Questions Test: Motion in a Straight Line questions and answers have been prepared according to the Grade 11 exam syllabus.The Case Based Questions Test: Motion in a Straight Line MCQs are made for Grade 11 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Case Based ...
NCERT Solutions for Class 11th: Ch 3 Motion In A Straight Line Physics
Since (AB + BC) > AC, average speed is greater than the magnitude of average velocity. The two quantities will be equal if the particle continues to move along a straight line. 3.14. A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km h-1.
Motion in a Straight Line: Crash Course Physics #1
Episode 1 | 10m 39s |. My List. In this, THE FIRST EPISODE of Crash Course Physics, your host Dr. Shini Somara introduces us to the ideas of motion in a straight line. She talks about displacement ...
Motion in a Straight Line Class 11 Important Extra Questions Physics
Question 9. The velocity of an object (ms -1) moving along a straight line is given by. v = 10 + 3t 2 …. (1) Find (a) change in velocity in the interval when t = 2s and 5s. (b) average acceleration in the same interval. (c) instantaneous acceleration at t = 4s. Answer:
NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line
Relative position of second stone w.r.t. first is given by x 2 (t) - x 1 (t) = 15t. Since there is a linear relationship between x 2 (t) - x 1 (t) and t, therefore the graph is a straight line. For maximum separation, t = 8 s So maximum separation is 120 m. After 8 second, only the second stone would be in motion.
CBSE 11th Physics Motion in a Straight Line Chapter Case Study
Motion in a Straight Line. CBSE 11th Physics Motion in a Straight Line Chapter Case Study Questions with Answers. 11th Physics CBSE case study questions for Motion in a Straight Line - 2024. CBSE 11th Physics Motion in a Straight Line Chapter Case Study Question with Answers. CBSE Class 11th Physics Sample Model Question Papers.
Motion In A straight Line, Distance And Displacement, Important Topics
Motion In A straight Line : Motion in a straight line is called straight motion. If the direction of a moving object is constant and the object is moving at a constant speed, then it is moving in a straight line. In this case, the object is said to be moving in a straight line at constant speed.
Motion In A Straight Line Notes for JEE Physics
By practising Motion In A Straight Line questions students can score well in advance level questions. Advantages of Motion In A Straight Line Notes for JEE. Students can be benefited with the help of Motion In A Straight Line Notes for JEE as this is a very important study tool. Some important advantages of the notes are:

Case Study Questions Class 11 Physics Motion in a Straight Line

Case Study – 2

Case Study – 5

Leave a Reply Cancel reply

Class 11 Physics Case Study Questions Chapter 3 Motion in a Straight Line

Motion in a Straight Line Case Study Questions With Answers

You Might Also Like

The Topper Combo Flashcards

CBSE Class 11 Physics Chapter 3 Motion in a Straight Line Study Materials

Kinematics: Motion in a Straight Line : Notes and Study Materials -pdf

Class 11 Physics Chapter 3 Motion in a Straight Line

Motion in a Straight Line Class 11 Notes Physics Chapter 3

Motion in a Straight Line Questions

Uniform Motion in a Straight Line

Non-uniform Motion in a Straight Line

Important Questions on Motion in a Straight Line

Practice Questions

Suggested Videos

Motion in One Dimension |Concepts visualised | Distance and Displacement | NEET| Aanand Sir

Uniform Motion and Non Uniform Motion

Motion Graphs | Velocity-Time Graph and Displacement-Time Graph

Leave a Comment Cancel reply

Register with BYJU'S & Download Free PDFs

Motion in a Straight Line - Explanation

What is Motion in a Straight Line?

Types of Linear Motion

Equations of Motion along a Straight Line

Motion in a Straight Line Formulas

Linear Motion Definition

Important Questions for Motion in a Straight Line

FAQs on Motion in a Straight Line

NCERT Study Material

PHYS101: Introduction to Mechanics

PHYS101 Study Guide

2b. Define and distinguish between vector and scalar physical quantities

2c. Explain the relationship between instantaneous and average values for physical quantities

2d. Compare and contrast speed and velocity

2e. Solve one-dimensional kinematics problems

2f. Describe the effects of gravity on an object in motion

2g. Calculate the position and velocity of an object in free fall

2h. Draw and interpret graphs for displacement and velocity as functions of time, and determine velocity and acceleration from them

Unit 2 Vocabulary

Conceptual Questions Based on Class 11 Physics Motion in A Straight Line

Conceptual Questions Based on Class 11 Physics

Download CBSE Books

Leave a Reply Cancel reply

Discover more from Gurukul of Excellence

CBSE Case Study Questions Class 11 Physics PDF Download

Class 11 Physics Case Study Questions

Chapter-wise Solved Case Study Questions for Class 11 Physics

Class 11 Books for Boards

Leave a Comment Cancel reply

Download India's best Exam Preparation App Now.

Case Based Questions Test: Motion in a Straight Line - Grade 11 MCQ

Top Courses for Grade 11

Important Questions for Case Based Questions Test: Motion in a Straight Line

Welcome Back

Forgot Password

NCERT Solutions for Class 11th: Ch 3 Motion In A Straight Line Physics

Contact Form

Motion in a Straight Line Class 11 Important Extra Questions Physics Chapter 3

Class 11 Physics Chapter 3 Important Extra Questions Motion in a Straight Line

Motion in a Straight Line Important Extra Questions Short Answer Type

Motion in a Straight Line Important Extra Questions Long Answer Type

NCERT Solutions for Class 11 Physics Chapter 3 Motion in a Straight Line

NCERT Solutions

NCERT Solutions for Class 11 Physics All Chapters

Free Resources

Quick Resources

Related 11th Standard CBSE Physics Materials

Class 11th Applied Mathematics - Coordinate Geometry Case Study Questions and Answers 2022 - 2023

Class VI to XII

11th Standard CBSE Study Materials

11th Standard CBSE Subjects

Motion In A straight Line, Distance And Displacement, Important Topics For JEE 2024

Rest, motion And Position In JEE Physics Syllabus

Distance In JEE Physics Syllabus

Displacement In JEE Physics Syllabus

Difference Between Distance And Displacement :

Distance And Displacement Examples